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The richardson equaction is given by I =...

The richardson equaction is given by `I = AT^(2) e^(-B//kT)`. The dimensional formula for `AB^(2)` is

A

1. IT^(2)`

B

2. `kT`

C

3. `Ik^(2)`

D

4. `Ik^(2)//T`

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To find the dimensional formula for \( AB^2 \) from the Richardson equation given by \[ I = AT^2 e^{-\frac{B}{kT}} \] we will follow these steps: ### Step 1: Understand the components of the equation The equation consists of: - \( I \): Current (with dimensions \([I]\)) - \( A \): A constant that we need to find the dimensions of - \( T \): Temperature (with dimensions \([\Theta]\)) - \( B \): Another constant whose dimensions we need to find - \( k \): Boltzmann's constant (with dimensions \([M^1 L^2 T^{-2} \Theta^{-1}]\)) ### Step 2: Analyze the exponential term The term \( e^{-\frac{B}{kT}} \) must be dimensionless. This means that the quantity \( \frac{B}{kT} \) must also be dimensionless. Therefore, we can write: \[ [B] = [k][T] \] ### Step 3: Write down the dimensions of \( k \) and \( T \) From the known dimensions: - \( [k] = [M^1 L^2 T^{-2} \Theta^{-1}] \) - \( [T] = [\Theta] \) ### Step 4: Substitute the dimensions into the equation Substituting the dimensions of \( k \) and \( T \) into the equation for \( B \): \[ [B] = [M^1 L^2 T^{-2} \Theta^{-1}][\Theta] = [M^1 L^2 T^{-2}] \] ### Step 5: Determine the dimensions of \( A \) From the Richardson equation, we can rearrange it to find \( A \): \[ I = A T^2 \implies [A] = \frac{[I]}{[T^2]} \] Since the dimensions of current \( I \) are \([I]\), we can write: \[ [A] = \frac{[I]}{[\Theta^2]} \] ### Step 6: Combine the dimensions to find \( AB^2 \) Now we need to find the dimensions of \( AB^2 \): \[ [AB^2] = [A][B^2] = \left(\frac{[I]}{[\Theta^2]}\right)[B]^2 \] Substituting the dimensions of \( B \): \[ [B^2] = [M^1 L^2 T^{-2}]^2 = [M^2 L^4 T^{-4}] \] Thus, \[ [AB^2] = \left(\frac{[I]}{[\Theta^2]}\right)[M^2 L^4 T^{-4}] = [I][M^2 L^4 T^{-4}][\Theta^{-2}] \] ### Final Result The dimensional formula for \( AB^2 \) is: \[ [AB^2] = [I][M^2 L^4 T^{-4}][\Theta^{-2}] \]

To find the dimensional formula for \( AB^2 \) from the Richardson equation given by \[ I = AT^2 e^{-\frac{B}{kT}} \] we will follow these steps: ...
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