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Young's modulus of steel is 1.9xx10^(11)...

Young's modulus of steel is `1.9xx10^(11) N//m^2` When expressed is CGS units of `dy"nes"// cm^2` it will be equal to `(1N = 10^5dy"ne", 1 m^2 = 10^4 cm^2)`

A

`1.9xx10^(10)`

B

`1.9xx10^(11)`

C

`1.9xx10^(12)`

D

`1.9xx10^(13)`

Text Solution

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The correct Answer is:
To convert Young's modulus from SI units (N/m²) to CGS units (dyne/cm²), we will follow these steps: ### Step 1: Write down the given value of Young's modulus in SI units. The Young's modulus of steel is given as: \[ Y = 1.9 \times 10^{11} \, \text{N/m}^2 \] ### Step 2: Convert Newtons to dynes. We know that: \[ 1 \, \text{N} = 10^5 \, \text{dyne} \] Thus, we can convert the Young's modulus from Newtons to dynes: \[ Y = 1.9 \times 10^{11} \, \text{N/m}^2 \times 10^5 \, \text{dyne/N} \] ### Step 3: Convert square meters to square centimeters. We also know that: \[ 1 \, \text{m}^2 = 10^4 \, \text{cm}^2 \] Now, we can express the Young's modulus in terms of dyne/cm²: \[ Y = \frac{1.9 \times 10^{11} \times 10^5 \, \text{dyne}}{1 \, \text{m}^2} \times \frac{1}{10^4 \, \text{cm}^2} \] ### Step 4: Simplify the expression. Now, we can simplify the expression: \[ Y = 1.9 \times 10^{11} \times 10^5 \times \frac{1}{10^4} \, \text{dyne/cm}^2 \] \[ Y = 1.9 \times 10^{11} \times 10^{5-4} \, \text{dyne/cm}^2 \] \[ Y = 1.9 \times 10^{11} \times 10^{1} \, \text{dyne/cm}^2 \] \[ Y = 1.9 \times 10^{12} \, \text{dyne/cm}^2 \] ### Final Answer: Thus, the Young's modulus of steel in CGS units is: \[ Y = 1.9 \times 10^{12} \, \text{dyne/cm}^2 \] ---

To convert Young's modulus from SI units (N/m²) to CGS units (dyne/cm²), we will follow these steps: ### Step 1: Write down the given value of Young's modulus in SI units. The Young's modulus of steel is given as: \[ Y = 1.9 \times 10^{11} \, \text{N/m}^2 \] ### Step 2: Convert Newtons to dynes. We know that: ...
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