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the work done against force of friction ...

the work done against force of friction is

A

8.7 J

B

10.7 J

C

7.8 J

D

12.7 J

Text Solution

Verified by Experts

The correct Answer is:
A
Work against friction is `W_f=fd=muNd=mumgcosthetad " " (therefore N=mgcos theta)`
`=0.1xx1 kg xx 10 m s^(-2) xx cos 30^@ xx 10 m`
=8.7 J
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