An adult weighing 600 N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs for 6 km, the energy utilised by him in jogging is

Options

A. `9xx10^6` J
B. `9xx10^5` J
C. `6xx10^6` J
D. `6xx10^5` J

Explanation

To solve the problem of calculating the energy utilized by an adult weighing 600 N while jogging for 6 km, we will follow these steps:

### Step 1: Identify the Given Data
- Weight of the adult (W) = 600 N
- Height raised per step (h) = 0.25 m
- Distance jogged = 6 km = 6000 m
- Length of each step = 1 m

### Step 2: Calculate the Number of Steps
To find the number of steps taken while jogging, we can use the formula:
\[ \text{Number of steps} = \frac{\text{Total distance jogged}}{\text{Length of each step}} \]
Substituting the values:
\[ \text{Number of steps} = \frac{6000 \text{ m}}{1 \text{ m}} = 6000 \text{ steps} \]

### Step 3: Calculate the Potential Energy Utilized
The energy utilized in raising the center of gravity can be calculated using the formula for gravitational potential energy:
\[ \text{Potential Energy (PE)} = \text{Number of steps} \times \text{Weight} \times \text{Height raised} \]
Substituting the values:
\[ \text{PE} = 6000 \text{ steps} \times 600 \text{ N} \times 0.25 \text{ m} \]

### Step 4: Perform the Calculation
Now, we calculate the potential energy:
\[ \text{PE} = 6000 \times 600 \times 0.25 = 6000 \times 150 = 900000 \text{ J} \]
Thus, the energy utilized by him in jogging is:
\[ \text{Energy utilized} = 9 \times 10^5 \text{ J} \]

### Final Answer
The energy utilized by the adult while jogging for 6 km is **900,000 J** or **9 x 10^5 J**.

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