Home
Class 11
PHYSICS
Calculate the amount of energy released ...

Calculate the amount of energy released in MeV due to a loss of mass of 1 kg.

A

3 MJ

B

30 MJ

C

300 MJ

D

3000 MJ

Text Solution

Verified by Experts

The correct Answer is:
B

When 1 kg of coal is burnt the energy released is 30 MJ `(=3 xx 10^7 J)`.
Promotional Banner

Topper's Solved these Questions

  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS ENGLISH|Exercise NCERT|18 Videos
  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS ENGLISH|Exercise ASSERTION & REASON|15 Videos
  • WAVES

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

A nuclear explosion is designed to deliver 1 MW of heat energy, how many fission events must be required in a second to attain this power level. If this explosion is designed with a nuclear fuel consisting of uranium 235 to run a reactor at this power level for one year, then calculate the amount of fuel needed. You can assume that the calculate the amount of energy released per fission event is 200 MeV .

Calculate the equivalent energy in MeV of a unified atomic mass unit.

A train of mass 100 tonnes is moving with a uniform speed of 2 ms^(-1) . Calculate the amount of energy possessed by the train. [Take 1 tonne=1000 kg] [200,000 J]

What is the amount of energy released by deuterium and tritum fusion ?

Find the amount of energy produced in joules due to fission of 1 gram of uranium assuming that 0.1 percent of mass is transformed into energy. Take 1amu= 1.66xx10^(-27)kg=931.5MeV Mass of uranium =235amu. Avogadro number = 6.02xx10^(23)

When U-235 undergoes fission, 0.1% of its mass is converted into energy. Then amount of energy released during the fission of 1kg of uranium-235 will be

find the amount of energy produced in jaoules due to fission of 1 g of ""._(92)U^(235) assuming that 0.1% of mass is transormed into enengy ,Atomic mass of ""._(92)U^(235)=235 amu , Avogodro number N_(A)=6.023xx10^(23). Given that the energy released per fission is 200 MeV.

Calculate the energy released when an electron annihilates a positron.

Calculate the energy in MeV equivalent to the rest mass of an electron . Given that the rest mass of an electron , m=9.1 xx 10^(-31) kg , 1MeV = 1.6 xx 10^(-13) J and speed of light , c= 3 xx 10 ^(8) ms ^(-1) .

The energy released during the fussion of 1 kg uranium is

NCERT FINGERTIPS ENGLISH-WORK , ENERGY AND POWER-Assertion And Reason
  1. Calculate the amount of energy released in MeV due to a loss of mass o...

    Text Solution

    |

  2. Assertion , No work is done if the displacement is zero Reason: Work...

    Text Solution

    |

  3. Assertion: Work done by the friction or viscous force on a moving body...

    Text Solution

    |

  4. Assertion: A light body and a heavy body have same momentum. Then they...

    Text Solution

    |

  5. Assertion:The work done by a conservative force such as gravity depend...

    Text Solution

    |

  6. Assertion : For two bodies , the sum of the mutual forces exerted betw...

    Text Solution

    |

  7. Assertion: Work done by the force of friction in moving a body around ...

    Text Solution

    |

  8. Assertion: Work done by friction over a closed path is not zero and no...

    Text Solution

    |

  9. Assertion: A spring has potential energy , both when it is compressed ...

    Text Solution

    |

  10. Assertion : The work done by the spring force in a cyclic process is z...

    Text Solution

    |

  11. Assertion: Universe as a whole may be viewed an isolted system. Rea...

    Text Solution

    |

  12. Assertion: Energy can neither be created nor destroyed. Reason: Th...

    Text Solution

    |

  13. Assertion: Energy associated with a mere kilogram of matter is 9 xx 10...

    Text Solution

    |

  14. Assertion : Kilowatt hour is the unit of power. Reason: One kilowa...

    Text Solution

    |

  15. Assertion: The conservation of kinetic energy in elastic collision app...

    Text Solution

    |

  16. Assertion: In a perfectly inelastic collision in the absence of extern...

    Text Solution

    |