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Assertion: The time period of revolution...

Assertion: The time period of revolution of a satellite close to surface of earth is smaller then that revolving away from surface of earth.
Reason: The square of time period of revolution of a satellite is directely proportioanl to cube of its orbital radius.

A

If both assertion and reason are true and reason is the correct explanation of assertion

B

If both assertion and reason are truebut reason is not the correct explanation of assertion

C

If assertion is true but reason is false

D

If both assertion and reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that "the time period of revolution of a satellite close to the surface of the Earth is smaller than that revolving away from the surface of the Earth." - This means that satellites that are closer to Earth complete their orbits faster than those that are further away. 2. **Understanding the Reason**: - The reason states that "the square of the time period of revolution of a satellite is directly proportional to the cube of its orbital radius." - This can be mathematically expressed as \( T^2 \propto r^3 \), where \( T \) is the time period and \( r \) is the orbital radius. 3. **Deriving the Relationship**: - We know that for a satellite in orbit, the gravitational force provides the necessary centripetal force. This can be expressed as: \[ \frac{GMm}{r^2} = \frac{mv^2}{r} \] where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, \( m \) is the mass of the satellite, and \( r \) is the orbital radius. - From this equation, we can derive the velocity \( v \) of the satellite: \[ v = \sqrt{\frac{GM}{r}} \] 4. **Finding the Time Period**: - The time period \( T \) of the satellite can be calculated using the formula: \[ T = \frac{2\pi r}{v} \] - Substituting the expression for \( v \): \[ T = \frac{2\pi r}{\sqrt{\frac{GM}{r}}} = 2\pi \sqrt{\frac{r^3}{GM}} \] 5. **Analyzing the Relationship**: - Squaring both sides gives: \[ T^2 = \frac{4\pi^2 r^3}{GM} \] - This shows that \( T^2 \) is directly proportional to \( r^3 \), confirming the reason provided. 6. **Conclusion**: - Since the assertion is true (satellites closer to Earth have a smaller time period) and the reason is also true (the relationship \( T^2 \propto r^3 \) is valid), we conclude that both the assertion and reason are correct, and the reason correctly explains the assertion. ### Final Answer: Both the assertion and reason are true, and the reason correctly explains the assertion. ---

To solve the question, we need to analyze the assertion and the reason provided. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that "the time period of revolution of a satellite close to the surface of the Earth is smaller than that revolving away from the surface of the Earth." - This means that satellites that are closer to Earth complete their orbits faster than those that are further away. ...
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