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Assertion : The ratio C(P)// C(upsilon) ...

Assertion : The ratio `C_(P)// C_(upsilon)` for a diatomic gas is more than that for a monoatomic gas.
Reason : The moleculess of a monoatomic gas have more degrees of freedom than those of a diatomic gas.

A

If both assertion and reason are true and reason is the correct explanation os assertion.

B

If both assertion and reason are true but reason is not be correct explanation of assertion.

C

If assertion is true but reason is false.

D

If both assertion and reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and reason provided regarding the specific heat capacities of monoatomic and diatomic gases. ### Step 1: Understanding the Assertion The assertion states that the ratio \( \frac{C_P}{C_V} \) for a diatomic gas is more than that for a monoatomic gas. ### Step 2: Specific Heat Capacities of Monoatomic Gas For a monoatomic gas: - The degrees of freedom \( f = 3 \) (only translational motion). - The specific heat at constant volume \( C_V = \frac{3}{2} R \). - The specific heat at constant pressure \( C_P = C_V + R = \frac{3}{2} R + R = \frac{5}{2} R \). Now, we can find the ratio: \[ \frac{C_P}{C_V} = \frac{\frac{5}{2} R}{\frac{3}{2} R} = \frac{5}{3} \] ### Step 3: Specific Heat Capacities of Diatomic Gas For a diatomic gas: - The degrees of freedom \( f = 5 \) (3 translational + 2 rotational). - The specific heat at constant volume \( C_V = \frac{5}{2} R \). - The specific heat at constant pressure \( C_P = C_V + R = \frac{5}{2} R + R = \frac{7}{2} R \). Now, we can find the ratio: \[ \frac{C_P}{C_V} = \frac{\frac{7}{2} R}{\frac{5}{2} R} = \frac{7}{5} \] ### Step 4: Comparing the Ratios Now we compare the ratios: - For monoatomic gas: \( \frac{C_P}{C_V} = \frac{5}{3} \) - For diatomic gas: \( \frac{C_P}{C_V} = \frac{7}{5} \) Since \( \frac{7}{5} > \frac{5}{3} \), the assertion is correct. ### Step 5: Understanding the Reason The reason states that the molecules of a monoatomic gas have more degrees of freedom than those of a diatomic gas. This statement is incorrect because: - Monoatomic gases have 3 degrees of freedom. - Diatomic gases have 5 degrees of freedom. ### Conclusion - The assertion is true: \( \frac{C_P}{C_V} \) for a diatomic gas is indeed more than that for a monoatomic gas. - The reason is false: Monoatomic gases do not have more degrees of freedom than diatomic gases. Thus, the final conclusion is: - Assertion: True - Reason: False

To solve the question, we need to analyze the assertion and reason provided regarding the specific heat capacities of monoatomic and diatomic gases. ### Step 1: Understanding the Assertion The assertion states that the ratio \( \frac{C_P}{C_V} \) for a diatomic gas is more than that for a monoatomic gas. ### Step 2: Specific Heat Capacities of Monoatomic Gas For a monoatomic gas: - The degrees of freedom \( f = 3 \) (only translational motion). ...
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