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If E , M , J , and G , respectively , de...

If `E , M , J , and G` , respectively , denote energy , mass , angular momentum , and gravitational constant , then `EJ^(2) //M^(5) G^(2)` has the dimensions of

A

length

B

mass

C

time

D

angle

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The correct Answer is:
To find the dimensions of the expression \( \frac{E J^2}{M^5 G^2} \), we will first determine the dimensions of each variable involved: energy (E), mass (M), angular momentum (J), and the gravitational constant (G). ### Step 1: Determine the dimensions of each variable. 1. **Energy (E)**: The dimensions of energy are given by: \[ [E] = [M][L^2][T^{-2}] = M^1 L^2 T^{-2} \] 2. **Mass (M)**: The dimensions of mass are: \[ [M] = M^1 \] 3. **Angular Momentum (J)**: Angular momentum is defined as the product of mass, velocity, and radius. Its dimensions can be expressed as: \[ [J] = [M][L][T^{-1}] \cdot [L] = M^1 L^2 T^{-1} \] 4. **Gravitational Constant (G)**: The dimensions of the gravitational constant can be derived from the formula for gravitational force: \[ F = \frac{G m_1 m_2}{r^2} \] Rearranging gives: \[ [G] = \frac{[F][L^2]}{[M]^2} = \frac{[M][L][T^{-2}][L^2]}{[M]^2} = M^{-1} L^3 T^{-2} \] ### Step 2: Substitute the dimensions into the expression. Now we substitute these dimensions into the expression \( \frac{E J^2}{M^5 G^2} \). 1. **Calculate \( J^2 \)**: \[ [J^2] = (M^1 L^2 T^{-1})^2 = M^2 L^4 T^{-2} \] 2. **Calculate \( G^2 \)**: \[ [G^2] = (M^{-1} L^3 T^{-2})^2 = M^{-2} L^6 T^{-4} \] ### Step 3: Combine the dimensions in the expression. Now we can substitute these into the expression: \[ \frac{E J^2}{M^5 G^2} = \frac{(M^1 L^2 T^{-2})(M^2 L^4 T^{-2})}{(M^5)(M^{-2} L^6 T^{-4})} \] ### Step 4: Simplify the expression. Now we simplify the dimensions: \[ = \frac{M^{1+2} L^{2+4} T^{-2-2}}{M^5 M^{-2} L^6 T^{-4}} = \frac{M^3 L^6 T^{-4}}{M^{5-2} L^6 T^{-4}} = \frac{M^3 L^6 T^{-4}}{M^3 L^6 T^{-4}} = 1 \] ### Step 5: Conclusion. The final result gives us: \[ [M^0 L^0 T^0] = 1 \] This indicates that the expression has no dimensions, which corresponds to an angle. ### Final Answer: The dimensions of \( \frac{E J^2}{M^5 G^2} \) are dimensionless, indicating it can be associated with an angle. ---
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