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If a body placed at the origin is acted ...

If a body placed at the origin is acted upon by a force `vecF=(hati+hatj+sqrt2hatk)`, then which of the following statements are correct?
Magnitude of `vecF` is (2+ `sqrt2`)
Magnitude of `vecF` is 2.
`vecF` makes an angle of `45^@` with the Z-axis
`vecF` makes an angle of `30^@` with the Z-axis.
Select the correct answer using the codes given below

A

1 and 3

B

2 and 3

C

1 and 4

D

2 and 4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the force vector given and determine the magnitude of the force and the angle it makes with the Z-axis. **Step 1: Identify the force vector.** The force vector is given as: \[ \vec{F} = \hat{i} + \hat{j} + \sqrt{2}\hat{k} \] **Step 2: Calculate the magnitude of the force vector.** The magnitude of a vector \(\vec{F} = a\hat{i} + b\hat{j} + c\hat{k}\) is calculated using the formula: \[ |\vec{F}| = \sqrt{a^2 + b^2 + c^2} \] For our vector: - \(a = 1\) (coefficient of \(\hat{i}\)) - \(b = 1\) (coefficient of \(\hat{j}\)) - \(c = \sqrt{2}\) (coefficient of \(\hat{k}\)) Now substituting these values into the formula: \[ |\vec{F}| = \sqrt{1^2 + 1^2 + (\sqrt{2})^2} = \sqrt{1 + 1 + 2} = \sqrt{4} = 2 \] **Step 3: Determine the angle with the Z-axis.** To find the angle \(\theta\) that the force vector makes with the Z-axis, we use the dot product formula: \[ \vec{F} \cdot \hat{k} = |\vec{F}| |\hat{k}| \cos \theta \] Here, \(\hat{k}\) is the unit vector in the Z-direction, which has a magnitude of 1. Calculating the dot product \(\vec{F} \cdot \hat{k}\): \[ \vec{F} \cdot \hat{k} = 0\hat{i} + 0\hat{j} + \sqrt{2}\hat{k} = \sqrt{2} \] Now substituting into the dot product equation: \[ \sqrt{2} = 2 \cdot 1 \cdot \cos \theta \] This simplifies to: \[ \sqrt{2} = 2 \cos \theta \] Dividing both sides by 2: \[ \cos \theta = \frac{\sqrt{2}}{2} \] From trigonometry, we know that: \[ \theta = 45^\circ \] **Final Results:** 1. The magnitude of \(\vec{F}\) is \(2\). 2. The angle \(\theta\) that \(\vec{F}\) makes with the Z-axis is \(45^\circ\). **Conclusion:** - The correct statements are: - Magnitude of \(\vec{F}\) is \(2\). - \(\vec{F}\) makes an angle of \(45^\circ\) with the Z-axis. Thus, the correct answer codes are 2 and 3. ---
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