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A particle is projected from the ground ...

A particle is projected from the ground with an initial speed `v` at an angle `theta` with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is `[EAM 2013]`

A

`u cos theta`

B

`u/2sqrt(1+cos^2 theta)`

C

`u/2sqrt(1+2 cos^2 theta)`

D

`u/2sqrt(1+3 cos^2 theta)`

Text Solution

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The correct Answer is:
D
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