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A bullet is fired normally towards an im...

A bullet is fired normally towards an immovable wooden block. If it loses `25 %` of its kinetic energy in penetrating through the block at thickness `x`, the distance penetrated by the bullet into the block is

A

4x

B

6x

C

8x

D

2x

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the situation using the concepts of kinetic energy and work done. ### Step-by-Step Solution: 1. **Understanding the Problem**: - A bullet is fired towards an immovable wooden block and penetrates a distance \( x \). - During this penetration, the bullet loses \( 25\% \) of its kinetic energy. 2. **Kinetic Energy Loss**: - Let the initial kinetic energy of the bullet be \( KE = \frac{1}{2} mv^2 \), where \( m \) is the mass of the bullet and \( v \) is its velocity. - The bullet loses \( 25\% \) of its kinetic energy while penetrating the block. Therefore, the energy lost is: \[ \text{Energy lost} = 0.25 \times KE = 0.25 \times \frac{1}{2} mv^2 = \frac{1}{8} mv^2 \] 3. **Work Done by the Bullet**: - According to the work-energy theorem, the work done by the bullet in penetrating the block is equal to the energy lost. - The work done can also be expressed as: \[ W = F \cdot x \] - Where \( F \) is the average resistive force exerted by the block on the bullet. 4. **Equating Work Done to Energy Lost**: - Setting the work done equal to the energy lost gives us: \[ F \cdot x = \frac{1}{8} mv^2 \] 5. **Total Kinetic Energy Consumption**: - When the bullet penetrates the block completely (let's say it penetrates a distance \( S \)), all of its kinetic energy will be converted into work done against the resistive force: \[ F \cdot S = KE = \frac{1}{2} mv^2 \] 6. **Relating the Two Equations**: - From the two equations we have: - \( F \cdot x = \frac{1}{8} mv^2 \) (1) - \( F \cdot S = \frac{1}{2} mv^2 \) (2) 7. **Dividing Equation (2) by Equation (1)**: - Dividing the second equation by the first gives: \[ \frac{F \cdot S}{F \cdot x} = \frac{\frac{1}{2} mv^2}{\frac{1}{8} mv^2} \] - Simplifying this, we find: \[ \frac{S}{x} = \frac{\frac{1}{2}}{\frac{1}{8}} = 4 \] - Therefore, we have: \[ S = 4x \] ### Final Answer: The distance penetrated by the bullet into the block is \( S = 4x \).
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