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Two identical flutes produce fundamental...

Two identical flutes produce fundamental notes of frequency `300Hz` at `27^@C`. If the temperature of air in one flute is increased to `31^@C`, the number of the beats heard per second will be

A

3

B

2

C

1

D

4

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the number of beats heard per second when the temperature of the air in one flute is increased from \(27^\circ C\) to \(31^\circ C\). ### Step-by-Step Solution: 1. **Understanding the relationship between frequency and temperature**: The speed of sound in air increases with temperature. The frequency of a sound wave is given by the formula: \[ v = n \cdot \lambda \] where \(v\) is the speed of sound, \(n\) is the frequency, and \(\lambda\) is the wavelength. 2. **Finding the speed of sound at different temperatures**: The speed of sound in air can be approximated by the formula: \[ v = \sqrt{\frac{\gamma R T}{M}} \] where \(T\) is the absolute temperature in Kelvin. The speed of sound is directly proportional to the square root of the temperature: \[ v \propto \sqrt{T} \] 3. **Converting temperatures to Kelvin**: Convert the given temperatures from Celsius to Kelvin: - \(T_1 = 27^\circ C = 27 + 273 = 300 \, K\) - \(T_2 = 31^\circ C = 31 + 273 = 304 \, K\) 4. **Calculating the change in frequency**: Since the frequency is related to the speed of sound, we can express the ratio of the speeds at the two temperatures: \[ \frac{v_2}{v_1} = \sqrt{\frac{T_2}{T_1}} = \sqrt{\frac{304}{300}} \] 5. **Calculating the new frequency**: The initial frequency \(n_1\) is given as \(300 \, Hz\). Therefore, the new frequency \(n_2\) can be calculated as: \[ n_2 = n_1 \cdot \frac{v_2}{v_1} = 300 \cdot \sqrt{\frac{304}{300}} \] 6. **Calculating the approximate value**: To simplify the calculation: \[ \sqrt{\frac{304}{300}} \approx \sqrt{1.0133} \approx 1.00665 \] Thus, \[ n_2 \approx 300 \cdot 1.00665 \approx 301.995 \, Hz \approx 302 \, Hz \] 7. **Finding the number of beats**: The number of beats per second is given by the absolute difference in frequencies of the two flutes: \[ \text{Beats} = |n_2 - n_1| = |302 - 300| = 2 \, Hz \] ### Final Answer: The number of beats heard per second will be \(2 \, Hz\).
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