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The coeefficient of volume expansion of...

The coeefficient of volume expansion of liquid is `gamma`. The fractional change in its density for `DeltaT` rise in tempeature is

A

`gammaDeltaT`

B

`(DeltaT)/(gamma)`

C

`1+ gamma Deltat`

D

`1- gamma DeltaT`

Text Solution

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The correct Answer is:
To find the fractional change in density of a liquid when the temperature rises by ΔT, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Coefficient of Volume Expansion**: The coefficient of volume expansion (γ) describes how the volume of a substance changes with temperature. The relationship can be expressed as: \[ V = V_0 (1 + \gamma \Delta T) \] where \( V_0 \) is the initial volume and \( \Delta T \) is the change in temperature. 2. **Relate Density to Volume**: Density (ρ) is defined as mass (m) divided by volume (V): \[ \rho = \frac{m}{V} \] If the mass of the liquid remains constant during the temperature change, any change in volume will affect the density. 3. **Express the New Density**: After the volume expands due to the temperature increase, the new density (ρ) can be expressed as: \[ \rho = \frac{m}{V} = \frac{m}{V_0 (1 + \gamma \Delta T)} \] 4. **Calculate the Initial Density**: The initial density (ρ₀) before the temperature change is: \[ \rho_0 = \frac{m}{V_0} \] 5. **Substitute for Volume in Density Equation**: Now, substituting the expression for volume into the density equation gives: \[ \rho = \frac{\rho_0 V_0}{V_0 (1 + \gamma \Delta T)} = \frac{\rho_0}{1 + \gamma \Delta T} \] 6. **Find the Change in Density**: The change in density (Δρ) can be calculated as: \[ \Delta \rho = \rho - \rho_0 = \frac{\rho_0}{1 + \gamma \Delta T} - \rho_0 \] To simplify this, we can write: \[ \Delta \rho = \rho_0 \left( \frac{1}{1 + \gamma \Delta T} - 1 \right) \] \[ = \rho_0 \left( \frac{1 - (1 + \gamma \Delta T)}{1 + \gamma \Delta T} \right) \] \[ = \rho_0 \left( \frac{-\gamma \Delta T}{1 + \gamma \Delta T} \right) \] 7. **Calculate the Fractional Change in Density**: The fractional change in density is given by: \[ \frac{\Delta \rho}{\rho_0} = \frac{-\gamma \Delta T}{1 + \gamma \Delta T} \] For small values of \( \gamma \Delta T \), we can approximate: \[ \frac{\Delta \rho}{\rho_0} \approx -\gamma \Delta T \] ### Final Answer: The fractional change in density for a ΔT rise in temperature is approximately: \[ \frac{\Delta \rho}{\rho_0} \approx -\gamma \Delta T \]
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