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Two absolute scales A and B have triple ...

Two absolute scales `A` and `B` have triple points of water defined to be `200A` and `350B`. What is the relation between `T_(A)` and `T_(B)`?

A

`T_(A) = 4//7 T_(B)`

B

`T_(B) = 4//7T_(A)`

C

`T_(A) = 2//7 T_(B)`

D

`T_(B) = 2//7 T_(A)`

Text Solution

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The correct Answer is:
To find the relation between the temperatures \( T_A \) and \( T_B \) on two absolute scales \( A \) and \( B \) with their respective triple points of water defined as \( 200A \) and \( 350B \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Triple Point of Water**: The triple point of water is a specific temperature where water can exist in three phases: solid, liquid, and gas. This temperature is defined to be \( 273.16 \, \text{K} \). 2. **Set Up the Equations**: Since the triple point of water is the same in both scales, we can equate the two definitions: \[ 200A = 273.16 \quad \text{(1)} \] \[ 350B = 273.16 \quad \text{(2)} \] 3. **Find the Temperature Unit for Scale A**: From equation (1), we can express one unit of scale \( A \) in terms of Kelvin: \[ 1A = \frac{273.16}{200} \, \text{K} \] 4. **Find the Temperature Unit for Scale B**: From equation (2), we can express one unit of scale \( B \) in terms of Kelvin: \[ 1B = \frac{273.16}{350} \, \text{K} \] 5. **Relate the Two Scales**: To find the relationship between \( T_A \) and \( T_B \), we can express \( T_A \) in terms of \( T_B \): \[ T_A = n_A \cdot 1A = n_A \cdot \frac{273.16}{200} \] \[ T_B = n_B \cdot 1B = n_B \cdot \frac{273.16}{350} \] 6. **Set the Equations Equal**: Since both temperatures correspond to the same physical condition (the triple point of water), we set the two equations equal: \[ \frac{273.16}{200} \cdot T_A = \frac{273.16}{350} \cdot T_B \] 7. **Cancel \( 273.16 \)**: We can cancel \( 273.16 \) from both sides: \[ \frac{T_A}{200} = \frac{T_B}{350} \] 8. **Cross Multiply**: Cross multiplying gives: \[ 350T_A = 200T_B \] 9. **Solve for \( T_A \)**: Rearranging gives: \[ T_A = \frac{200}{350} T_B = \frac{4}{7} T_B \] ### Final Relation: Thus, the relation between \( T_A \) and \( T_B \) is: \[ T_A = \frac{4}{7} T_B \]

To find the relation between the temperatures \( T_A \) and \( T_B \) on two absolute scales \( A \) and \( B \) with their respective triple points of water defined as \( 200A \) and \( 350B \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Triple Point of Water**: The triple point of water is a specific temperature where water can exist in three phases: solid, liquid, and gas. This temperature is defined to be \( 273.16 \, \text{K} \). 2. **Set Up the Equations**: ...
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