Home
Class 11
PHYSICS
Rays from the sun ar focuseed by a lens...

Rays from the sun ar focuseed by a lens of diameter 5 cm on to a block of ice and 10 g of ice is melted in 20 min. Therefore the heat from the sun reaching the earth per min per square centrimetre is
(Latent heat of ice `L = 80 cal g^(-1)`)

A

`2.04 cal`

B

`0.51 cal`

C

`4.08 cal`

D

`3.02 cal`

Text Solution

Verified by Experts

The correct Answer is:
A

If s calorie of heat is received from the sun per `cm^(2)` per minute, the heat collected by the lens of radius `2.5 cm^(2)` in `20` mintues is
`Q_(1) = s xx A xx t = s xx pi xx (2.5)^(2) xx (20) = (392.5) s cal`
Heat required to melt `10 g` of ice is
`Q_(2) = mL = 10 xx 80 = 800 cal`
According to given problem `Q_(1) = Q_(2)`
`:. 392.5 s = 800` or `s= 2.04 cal cm^(-2) min^(-1)`
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Heat Transper|29 Videos
  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Higher Order|8 Videos
  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Calorimetery|4 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTIONS

    NCERT FINGERTIPS ENGLISH|Exercise NCERT Exemplar|8 Videos
  • THERMODYNAMICS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

The rays of the sun are focused on a piece of ice through a lens of diameter 5 cm , as a result of which 10g ice melts in 10 minutes. The amount of heat received from the sun per unit area per minute is

How much heat energy is required to melt 5 kg of ice ? Specific latent heat of ice = 336 J g^(-1)

A coil of water of resistance 50 Omega is embedded in a block of ice and a potential difference of 210 V is applied across it. The amount of ice which melts in 1 second is [ latent heat of fusion of ice = 80 cal g^(-1) ]

10 g of ice at 0 C is slowly melted to water at 0 C. The latent heat of melting is 80 cal /g. the change in entropy is ?(cal/k)

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

An iron ball of mass 0.2 kg is heated to 10^(@)C and put into a block of ice at 0^(@)C . 25 g of ice melts. If the latent heat of fusion of ice is 80 cal g^(-1) , then the specific heat of iron in cal g^(-1^(@))C is

Sunrays are allowed to fall on a lens of diameter 20 cm. They are then brought to focus on a calorimeter containing 20 g of ice. If the absorption by the lens is neglible, the time required to melt all the ice is (solar constant = 1.9 cal min^(-1) cm^(-2) and L = 80 calg^(-1) )

One end of a 0.25 m long metal bar is in steam and the other is in contact with ice . If 12 g of ice melts per minute, what is the thermal conductivity of the metal? Given cross-section of the bar =5xx10^(-4) m^(2) and latent heat of ice is 80 cal g^(-1)

Calculate the entropy change in the melting of 1 kg of ice at 0^(@)C in SI units. Heat of funsion of ice = 80 cal g^(-1) .

When 1 kg of ice at 0^(@)C melts to water at 0^(@)C , the resulting change in its entropy, taking latent heat of ice to be 80 cal//g is