Home
Class 11
PHYSICS
Two rods of equal length and diameter ha...

Two rods of equal length and diameter have thermal conductivite 3 and 4 units respectively. If they are joined in series, the thermal conductivity of the combination in the given units would be

A

`3.43`

B

`4.43`

C

`5.43`

D

`2.43`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equivalent thermal conductivity of two rods joined in series, we can follow these steps: ### Step 1: Understand the Given Information We have two rods with the following properties: - Length of both rods (L1 and L2) = L (equal for both) - Diameter of both rods = same (implying equal cross-sectional area) - Thermal conductivity of the first rod (k1) = 3 units - Thermal conductivity of the second rod (k2) = 4 units ### Step 2: Calculate the Thermal Resistance of Each Rod The thermal resistance (R) of a rod can be calculated using the formula: \[ R = \frac{L}{k \cdot A} \] where: - \(L\) = length of the rod - \(k\) = thermal conductivity - \(A\) = cross-sectional area For the first rod (R1): \[ R_1 = \frac{L}{k_1 \cdot A} = \frac{L}{3 \cdot A} \] For the second rod (R2): \[ R_2 = \frac{L}{k_2 \cdot A} = \frac{L}{4 \cdot A} \] ### Step 3: Find the Total Thermal Resistance When two resistances are in series, the total resistance (R_equivalent) is the sum of the individual resistances: \[ R_{\text{equivalent}} = R_1 + R_2 = \frac{L}{3A} + \frac{L}{4A} \] To add these fractions, find a common denominator (which is 12A): \[ R_{\text{equivalent}} = \frac{4L}{12A} + \frac{3L}{12A} = \frac{7L}{12A} \] ### Step 4: Relate Total Resistance to Equivalent Thermal Conductivity The equivalent thermal resistance can also be expressed in terms of the equivalent thermal conductivity (k_equivalent): \[ R_{\text{equivalent}} = \frac{L}{k_{\text{equivalent}} \cdot A} \] Setting the two expressions for \(R_{\text{equivalent}}\) equal to each other: \[ \frac{L}{k_{\text{equivalent}} \cdot A} = \frac{7L}{12A} \] ### Step 5: Solve for k_equivalent Cancel \(L\) and \(A\) from both sides: \[ \frac{1}{k_{\text{equivalent}}} = \frac{7}{12} \] Taking the reciprocal gives: \[ k_{\text{equivalent}} = \frac{12}{7} \] ### Step 6: Calculate the Numerical Value Now, calculate the numerical value: \[ k_{\text{equivalent}} = \frac{12}{7} \approx 1.714 \text{ units} \] ### Conclusion The equivalent thermal conductivity of the combination of the two rods joined in series is approximately **1.714 units**. ---

To find the equivalent thermal conductivity of two rods joined in series, we can follow these steps: ### Step 1: Understand the Given Information We have two rods with the following properties: - Length of both rods (L1 and L2) = L (equal for both) - Diameter of both rods = same (implying equal cross-sectional area) - Thermal conductivity of the first rod (k1) = 3 units - Thermal conductivity of the second rod (k2) = 4 units ...
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Higher Order|8 Videos
  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Exampler Problems|8 Videos
  • THERMAL PROPERTIES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Change of State|13 Videos
  • SYSTEM OF PARTICLES AND ROTATIONAL MOTIONS

    NCERT FINGERTIPS ENGLISH|Exercise NCERT Exemplar|8 Videos
  • THERMODYNAMICS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Statement I: Two solid cylindrical rods of identical size and different thermal conductivity K_1 and K_2 are connected in series. Then the equivalent thermal conductivity of two rods system is less than that value of thermal conductivity of either rod. Statement II: For two cylindrical rods of identical size and different thermal conductivity K_1 and K_2 connected in series, the equivalent thermal conductivity K is given by (2)/(K)=(1)/(K_1)+(1)/(K_2)

Statement I: Two solid cylindrical rods of identical size and different thermal conductivity K_1 and K_2 are connected in series. Then the equivalent thermal conductivity of two rods system is less than that value of thermal conductivity of either rod. Statement II: For two cylindrical rods of identical size and different thermal conductivity K_1 and K_2 connected in series, the equivalent thermal conductivity K is given by (2)/(K)=(1)/(K_1)+(1)/(K_2)

Three rods of the same dimension have thermal conductivity 3K , 2K and K. They are arranged as shown in the figure below Then , the temperature of the junction in steady - state is

Consider a compound slab consisting of two different material having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is

Consider a compound slab consisting of two different material having equal thickness and thermal conductivities K and 2K respectively. The equivalent thermal conductivity of the slab is

Two conducting wires of the same material and of equal length and equal diameters are first connected in series and then in parallel in an electric circuit. The ratio of the heat produced in series and parallel combinations would be :

Two rods P and Q of equal lengths have thermal conductivities K_(1) and K_(2) and cross-sectional areas A_(1) and A_(2) respectively. If the temperature difference across the ends of each rod is the same, then the condition for which the rate of flow of heat through each of them will be equal, is

Three rods of same dimensions have thermal conductivity 3K,2K and K They are arranged as shown in Then the temperature of the junction in steady state is .

Three rods of same dimension are joined in series having thermal conductivity k_1 , k_2 and k_3 . The equivalent thermal conductivity is

Two identical plates with thermal conductivities K and 3K are joined together to form a single plate of double thickness. The equivalent thermal conductivity of one composite plate so formed for the flow of heat through its thickness is.

NCERT FINGERTIPS ENGLISH-THERMAL PROPERTIES OF MATTER-Heat Transper
  1. In the question number of 45, the equivalent thermal conductivity of t...

    Text Solution

    |

  2. Consider a compound slab consisting of two different material having e...

    Text Solution

    |

  3. Two rods of equal length and diameter have thermal conductivite 3 and ...

    Text Solution

    |

  4. Three metal rods of the same material and identical in all respect are...

    Text Solution

    |

  5. Three very large plates of same area are kept parrallel and close to e...

    Text Solution

    |

  6. A cubical ice box of side 50 cm has a thickness of 5.0 cm. if 5 kg of ...

    Text Solution

    |

  7. A wall has two layers A and B, each made of different material. Both t...

    Text Solution

    |

  8. Mud houses are cooler in summer and warmer in winter because

    Text Solution

    |

  9. Which of the following is the v(m) = T graph for a perfectly black bod...

    Text Solution

    |

  10. The equatorial and polar regions of the earth receive unequal sol...

    Text Solution

    |

  11. In which of the following process, convection does not take place pri...

    Text Solution

    |

  12. Wien's displacment law expresses relation between

    Text Solution

    |

  13. If lambda(m) denotes

    Text Solution

    |

  14. A black body has maximum wavelength lambda(m) at temperature 2000 K. I...

    Text Solution

    |

  15. The thermal radiation from a hot body travels with a velocity...

    Text Solution

    |

  16. Experimental investigations show that the intensity of solar radiat...

    Text Solution

    |

  17. The wavelength of maximum intensity of radiation emitted by a star is ...

    Text Solution

    |

  18. The temperature of a radiation body increases by 30 %. Then the in...

    Text Solution

    |

  19. If the temperature of hot black body is raised by 5%, rate of heat e...

    Text Solution

    |

  20. Two spheres of same material have radius 1 m and 4 m and temperature 4...

    Text Solution

    |