1 ampere current is equivalent to

Options

A. `6.25xx10^(-18)` electrons `s^(-1)`
B. `2.25xx10^(-18)` electrons `s^(-1)`
C. `6.25xx10^(14)` electrons `s^(-1)`
D. `2.25xx10^(14)` electrons `s^(-1)`

Explanation

To define 1 ampere of current, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Current**:
- Current (I) is defined as the flow of electric charge. The formula for current is given by:
\[ I = \frac{Q}{T} \]
where \( Q \) is the charge and \( T \) is the time.

2. **Rearranging the Formula**:
- From the formula, we can rearrange it to find the charge:
\[ Q = I \times T \]

3. **Defining 1 Ampere**:
- To define 1 ampere, we need to set \( I = 1 \) ampere and \( T = 1 \) second:
\[ Q = 1 \, \text{A} \times 1 \, \text{s} = 1 \, \text{coulomb} \]
- Therefore, 1 ampere of current is equivalent to a charge of 1 coulomb flowing in 1 second.

4. **Quantization of Charge**:
- The charge can also be expressed in terms of the number of electrons. The charge of a single electron (e) is approximately \( 1.6 \times 10^{-19} \) coulombs.
- The total charge can be expressed as:
\[ Q = n \times e \]
where \( n \) is the number of electrons.

5. **Finding the Number of Electrons**:
- Substituting \( Q \) into the equation gives:
\[ n \times e = I \times T \]
- For \( I = 1 \) ampere and \( T = 1 \) second, we have:
\[ n \times (1.6 \times 10^{-19}) = 1 \]
- Rearranging for \( n \):
\[ n = \frac{1}{1.6 \times 10^{-19}} \approx 6.25 \times 10^{18} \]

6. **Conclusion**:
- Thus, 1 ampere of current corresponds to approximately \( 6.25 \times 10^{18} \) electrons flowing through a conductor in 1 second.