In an atom electrons revolves around the nucleus along a path of radius 0.72Ã… making `9.4xx 10^(18)` revolution per second. The equivalent current is `(e=1.6xx10^(-19) C) `

Options

A. 1.2A
B. 1.5A
C. 1.4A
D. 1.8A

Explanation

To find the equivalent current generated by an electron revolving around the nucleus of an atom, we can follow these steps:

### Step 1: Understand the problem
We are given:
- The radius of the electron's orbit, \( r = 0.72 \, \text{Å} = 0.72 \times 10^{-10} \, \text{m} \)
- The frequency of revolution, \( f = 9.4 \times 10^{18} \, \text{revolutions/second} \)
- The charge of an electron, \( e = 1.6 \times 10^{-19} \, \text{C} \)

### Step 2: Determine the time period of revolution
The time period \( T \) is the reciprocal of the frequency \( f \):
\[ T = \frac{1}{f} \]
Substituting the value of \( f \):
\[ T = \frac{1}{9.4 \times 10^{18}} \approx 1.064 \times 10^{-19} \, \text{s} \]

### Step 3: Calculate the current
The current \( I \) can be calculated using the formula:
\[ I = \frac{Q}{T} \]
Where \( Q \) is the charge that passes through a point in the circuit in time \( T \). Since one electron completes one revolution and contributes its charge \( e \) in that time, we can write:
\[ I = \frac{e}{T} \]
Substituting the values of \( e \) and \( T \):
\[ I = \frac{1.6 \times 10^{-19}}{1.064 \times 10^{-19}} \approx 1.504 \, \text{A} \]

### Final Result
The equivalent current is approximately \( I \approx 1.504 \, \text{A} \).

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