The battery of a trunk has an emf of 24 V. If the internal resistance of the battery is `0.8Omega`. What is the maximum current that can be drawn from the battery?

Options

A. 30A
B. 32A
C. 33A
D. 34A

Explanation

To find the maximum current that can be drawn from the battery, we can use the formula for current in a circuit with a battery and internal resistance. Here are the steps to solve the problem:

### Step-by-Step Solution:

1. **Identify the given values:**
- Electromotive force (emf) of the battery, \( E = 24 \, \text{V} \)
- Internal resistance of the battery, \( r = 0.8 \, \Omega \)

2. **Understand the condition for maximum current:**
- The maximum current (\( I_{\text{max}} \)) can be drawn from the battery when the external resistance (\( R \)) is zero. In this case, the entire emf of the battery is available to drive the current through the internal resistance.

3. **Use the formula for maximum current:**
- The formula for current (\( I \)) in a circuit with internal resistance is given by:
\[ I = \frac{E}{R + r} \]
- For maximum current, set \( R = 0 \):
\[ I_{\text{max}} = \frac{E}{r} \]

4. **Substitute the values into the formula:**
\[ I_{\text{max}} = \frac{24 \, \text{V}}{0.8 \, \Omega} \]

5. **Calculate the maximum current:**
\[ I_{\text{max}} = \frac{24}{0.8} = 30 \, \text{A} \]

6. **Conclusion:**
- The maximum current that can be drawn from the battery is \( 30 \, \text{A} \).

### Final Answer:
The maximum current that can be drawn from the battery is **30 A**.

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