Home
Class 12
PHYSICS
Assertion: Kirchhoff's junction rule can...

Assertion: Kirchhoff's junction rule can be applied to a juction of several lines or a point in a line.
Reason : When steady current is flowing, there is no accumulation of charges at any junction in series with a galvonometer.

A

If both assertion and reason are true and reason is the correct explantion of assertion.

B

If both assertion and reason are true and reason is not the correct explantion of assertion.

C

If assertion is false but reason is true.

D

If assertion is true but reason is false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion-reason question, we need to analyze both the assertion and the reason provided. ### Step 1: Analyze the Assertion The assertion states that "Kirchhoff's junction rule can be applied to a junction of several lines or a point in a line." - Kirchhoff's junction rule, also known as Kirchhoff's first law or the current law, states that the total current entering a junction must equal the total current leaving the junction. - This rule applies to any junction where multiple conductors meet, regardless of whether they are in series or parallel. **Conclusion for Step 1**: The assertion is true. ### Step 2: Analyze the Reason The reason states that "When steady current is flowing, there is no accumulation of charges at any junction in series with a galvanometer." - In a steady state (DC current), the charge does not accumulate at any junction because the current is constant. - If there were an accumulation of charge, it would indicate that the current is changing, which contradicts the definition of steady current. - The presence of a galvanometer does not affect the application of Kirchhoff's junction rule; it simply measures the current flowing through the circuit. **Conclusion for Step 2**: The reason is also true. ### Step 3: Determine the Relationship Now we need to determine if the reason correctly explains the assertion. - While both the assertion and the reason are true, the reason does not directly explain the assertion. The assertion is about the application of Kirchhoff's junction rule, while the reason discusses the behavior of charge at a junction with steady current. ### Final Conclusion - The assertion is true, and the reason is true, but the reason does not explain the assertion. Therefore, the correct answer is that both statements are true, but the reason is not the correct explanation for the assertion.
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    NCERT FINGERTIPS ENGLISH|Exercise Ohm'S Law|7 Videos

  • CURRENT ELECTRICITY

    NCERT FINGERTIPS ENGLISH|Exercise Drift Of Electrons And The Origin Of Resistivity|2 Videos

  • CURRENT ELECTRICITY

    NCERT FINGERTIPS ENGLISH|Exercise EXEMPLAR PROBLEMS|6 Videos

  • COMMUNITCATION SYSTEMS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|30 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Assertion : With the help of Gauss's theorm we can find electric field at any point. Reason : Gauss's theorem can be applied for any type of charge distribution.

Assertion: Number of triangles formed by n concurrent lines and a line which is parallel to one of the n concurrent lines is "^(n-1)C_2. Reason: One and only one triangle is formed by three lines out of which 2 are concurrent and third line is not passing through the point of intersection of the concurrent lines and not parallel to any of the concurrent lines. (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not the correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

When a silicon PN junction is in forwards biased condition with series resistance, it has knee voltage of 0.6 V . Current flow in it is 5 mA , when PN junction is connected with 2.6 V battery, the value of series resistance is

Assertion : When two semi conductor of p and n type are brought in contact, they form p-n junction which act like a rectifier. Reason : A rectifier is used to convent alternating current into direct current.

Assertion : Current between two points in an electrical always flows from higher potential to lower potential. Reason : During charging of a battery current inside the battery flows negative terminal to positive terminal.

In p-n junction diode, near junction holes combine with electrons, and impurity ions form a barrier potential which opposes the recombination of electron-hole pairs. Value of barriers potential for Si is 0.7 volt and for Ge is 0.3 V. thus charge density at the junction becomes zero and an electric field is produced near junction. this region is called depletion layer. Thickness of depletion layer is of the order of 10^(-6) meter. in forward bias p terminal is connected with the positive terminal of cell and n is connected with negative terminal of cell and n is connected with negative terminal of cell. as forward voltage is increased, current increases exponentially. For Si diode minimum required forward voltage so that current can flow is

Assertion: Magnetic field strength at a point on axial line of a bar magnet is along South to North pole of magnet. Reason: The magnetic field strength can never be along North to South pole of magnet.

In a thin rectangular metallic strip a constant current I flows along the positive x-direction , as shown in the figure. The length , width and thickness of the strip are l, w and d , respectively. A uniform magnetic field vec(B) is applied on the strip along the positive y- direction . Due to this, the charge carriers experience a net deflection along the z- direction . This results in accumulation of charge carriers on the surface PQRS ansd apperance of equal and opposite charges on the face opposite to PQRS . A potential difference along the z-direction is thus developed. Charge accumulation contiues untill the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross- section of the strip and carried by electrons. Consider two different metallic strips (1 and 2) of the same material . Their lengths are the same,widths are w_(1) and w_(2) and thickness are d_(1) and d_(2) respectively. Two points K and M are symmetrically located on the opposite faces parallel to the x-y plane ( see figure) . V_(1) and V_(2) are the potential differences between K and M in strips 1 and 2 , respectively . Then, for a given current I flowing through them in a given magnetic field strength B , the correct statement(s) is (are)

In a thin rectangular metallic strip a constant current I flows along the positive x-direction , as shown in the figure. The length , width and thickness of the strip are l, w and d , respectively. A uniform magnetic field vec(B) is applied on the strip along the positive y- direction . Due to this, the charge carriers experience a net deflection along the z- direction . This results in accumulation of charge carriers on the surface PQRS ansd apperance of equal and opposite charges on the face opposite to PQRS . A potential difference along the z-direction is thus developed. Charge accumulation contiues untill the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross- section of the strip and carried by electrons. Consider two different metallic strips (1 and 2) of the same material . Their lengths are the same,widths are w_(1) and w_(2) and thickness are d_(1) and d_(2) respectively. Two points K and M are symmetrically located on the opposite faces parallel to the x-y plane ( see figure) . V_(1) and V_(2) are the potential differences between K and M in strips 1 and 2 , respectively . Then, for a given current I flowing through them in a given magnetic field strength B , the correct statement(s) is (are)

Assertion A point charge produces a uniform electric field. Reason Due to a point charge, electric lines of forces are parallel and equidistant.