The rms value of current in an ac circuit is 25 A, then peak current is

Options

A. `35.36 mA`
B. `35.36 A`
C. `3.536 A`
D. `49.38 A`

Explanation

To find the peak current (I₀) in an AC circuit when the RMS current (I_rms) is given, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between RMS current and peak current**:
The RMS (Root Mean Square) value of current in an AC circuit is related to the peak current by the formula:
\[ I_{rms} = \frac{I_0}{\sqrt{2}} \]
where \(I_0\) is the peak current.

2. **Rearrange the formula to find peak current**:
To find the peak current \(I_0\), we can rearrange the formula:
\[ I_0 = I_{rms} \times \sqrt{2} \]

3. **Substitute the given RMS value**:
We are given that \(I_{rms} = 25 \, \text{A}\). Now, substitute this value into the rearranged formula:
\[ I_0 = 25 \, \text{A} \times \sqrt{2} \]

4. **Calculate \(\sqrt{2}\)**:
The value of \(\sqrt{2}\) is approximately \(1.414\). Therefore, we can calculate:
\[ I_0 = 25 \, \text{A} \times 1.414 \]

5. **Perform the multiplication**:
Now, calculate the product:
\[ I_0 \approx 25 \times 1.414 \approx 35.35 \, \text{A} \]

6. **Final result**:
Thus, the peak current \(I_0\) is approximately \(35.35 \, \text{A}\).

### Final Answer:
The peak current is approximately \(35.35 \, \text{A}\).