The phase relationship between current and voltage in a pure resistive circuit is best represented by

Options

A.
B.
C.
D.

Explanation

To determine the phase relationship between current and voltage in a pure resistive circuit, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Components of the Circuit**:
- In a pure resistive circuit, the only component present is a resistor connected to an AC voltage source.

2. **Voltage and Current Equations**:
- The voltage across the resistor can be expressed as:
\[ V(t) = V_0 \sin(\omega t) \]
- The current flowing through the resistor can be expressed as:
\[ I(t) = I_0 \sin(\omega t) \]

3. **Identify the Phase Relationship**:
- Both the voltage and current equations have the same angular frequency (\(\omega\)) and the same time variable (\(t\)). This indicates that the voltage and current reach their maximum and minimum values at the same time.

4. **Determine Phase Difference**:
- Since both the voltage and current waveforms are represented by the same sine function, the phase difference (\(\phi\)) between them is:
\[ \phi = 0 \]
- This means that the voltage and current are in phase.

5. **Graphical Representation**:
- If we were to draw the waveforms for both voltage and current, they would oscillate together, reaching their peaks and troughs simultaneously. The voltage waveform would have a peak value of \(V_0\) and the current waveform would have a peak value of \(I_0\).

6. **Conclusion**:
- In a pure resistive circuit, the phase relationship between current and voltage is such that they are in phase, which can be summarized as:
\[ \text{Phase difference } \phi = 0 \]

### Final Answer:
The phase relationship between current and voltage in a pure resistive circuit is best represented by the fact that they are in phase, meaning the phase difference is \(0\).

---