A 44 mH inductor is connected to 220 V, 50 Hz ac supply. The rms value of the current in the circuit is

Options

A. `12.8 A`
B. `13.6 A`
C. `15.9 A`
D. `19.5 A`

Answer

C

Explanation

Here, `L = 44 mH = 44xx10^(-3)H`
`V_("rms")=220 V, upsilon = 50 Hz`
The inductive reactance is
`X_(L)= omega L = 2pi upsilon L = 2xx3.14xx50xx44xx50xx44xx10^(-3)=13.82 Omega`
`therefore I_("rms")= (V_("rms"))/(X_(L))=(220)/(13.82)=15.0 A`