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A circuit containing a 20 Omega resistor...

A circuit containing a `20 Omega` resistor and `0.1 mu F` capacitor in series is connected to 320 V ac supply of angular frequency `100 " rad " s^(-1)`. The impedance of the circuit is

A

`10^(5)Omega`

B

`10^(4)Omega`

C

`10^(6)Omega`

D

`10^(10)Omega`

Text Solution

Verified by Experts

The correct Answer is:
A

Here, `R = 20 Omega, C = 0.1 mu F =0.1xx10^(-6)F =10^(-7)F`
Impedance, `Z=sqrt(R%^(2)+(1)/(omega^(2)C^(2)))`
`=sqrt(20^(2)+(1)/((100)^(2)xx(10^(-7))^(2)))=sqrt(400+10^(10))~=10^(5)Omega`
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