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In a series L-R circuit (L=35 mH and R=1...

In a series L-R circuit `(L=35 mH and R=11 Omega)`, a variable emf source `(V=V_(0) sin omega t)` of `V_(rms)=220V` and frequency 50 Hz is applied. Find the current amplitude in the circuit and phase of current with respect to voltage. Draw current-time graph on given graph `(pi=22/7)`.

A

`10 A`

B

20 A

C

30 A

D

40 A

Text Solution

Verified by Experts

The correct Answer is:
B
`X_(L)=omegaL=(2pixx50) (35xx10^(-3))=11 Omega`
`therefore` Impedance `Z = sqrt(R^(2)+X_(L)^(2)), Z = sqrt((11)^(2)+(11)^(2))=11sqrt(2)Omega`
`therefore I_(0) = (V_(0))/(Z)=(V_("rms")xxsqrt(2))/(11sqrt(2))=(220)/(11)=20 A`
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