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The two slits are 1 mm apart from each o...

The two slits are 1 mm apart from each other and illuminated with a light of wavelength `5xx10^(-7)` m. If the distance of the screen is 1 m from the slits, then the distance between third dark fringe and fifth bright fringe is

A

1.2 mm

B

0.75 mm

C

1.25 mm

D

0.625 mm

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To find the distance between the third dark fringe and the fifth bright fringe in a double-slit experiment, we can follow these steps: ### Step 1: Identify the given values - Distance between the slits (d) = 1 mm = \(1 \times 10^{-3}\) m - Wavelength of light (\(\lambda\)) = \(5 \times 10^{-7}\) m - Distance from the slits to the screen (D) = 1 m ### Step 2: Calculate the position of the fifth bright fringe The position of the nth bright fringe from the center is given by the formula: \[ y_n = \frac{n \cdot D \cdot \lambda}{d} \] For the fifth bright fringe (\(n = 5\)): \[ y_5 = \frac{5 \cdot D \cdot \lambda}{d} \] Substituting the values: \[ y_5 = \frac{5 \cdot 1 \cdot 5 \times 10^{-7}}{1 \times 10^{-3}} = \frac{25 \times 10^{-7}}{10^{-3}} = 25 \times 10^{-4} \text{ m} = 2.5 \times 10^{-3} \text{ m} = 2.5 \text{ mm} \] ### Step 3: Calculate the position of the third dark fringe The position of the nth dark fringe from the center is given by the formula: \[ y_{n} = \frac{(n - 0.5) \cdot D \cdot \lambda}{d} \] For the third dark fringe (\(n = 3\)): \[ y_3 = \frac{(3 - 0.5) \cdot D \cdot \lambda}{d} = \frac{2.5 \cdot D \cdot \lambda}{d} \] Substituting the values: \[ y_3 = \frac{2.5 \cdot 1 \cdot 5 \times 10^{-7}}{1 \times 10^{-3}} = \frac{12.5 \times 10^{-7}}{10^{-3}} = 12.5 \times 10^{-4} \text{ m} = 1.25 \times 10^{-3} \text{ m} = 1.25 \text{ mm} \] ### Step 4: Calculate the distance between the fifth bright fringe and the third dark fringe The distance between the fifth bright fringe and the third dark fringe is given by: \[ \text{Distance} = y_5 - y_3 \] Substituting the values: \[ \text{Distance} = 2.5 \text{ mm} - 1.25 \text{ mm} = 1.25 \text{ mm} \] ### Final Answer The distance between the third dark fringe and the fifth bright fringe is **1.25 mm**. ---

To find the distance between the third dark fringe and the fifth bright fringe in a double-slit experiment, we can follow these steps: ### Step 1: Identify the given values - Distance between the slits (d) = 1 mm = \(1 \times 10^{-3}\) m - Wavelength of light (\(\lambda\)) = \(5 \times 10^{-7}\) m - Distance from the slits to the screen (D) = 1 m ### Step 2: Calculate the position of the fifth bright fringe ...
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  9. Statement-I : In Young's double slit experiment interference pattern d...

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  10. Assertion : The fringe closest on either side of the central white fri...

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  15. Assertion : In interference and diffraction, light energy is redistrib...

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