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In a Fraunhofer diffraction at single sl...

In a Fraunhofer diffraction at single slit of width d with incident light of wavelength 5500 Ã…, the first minimum is observed, at angle `30^(@)`. The first secondary maximum is observed at an angle `theta=`

A

`"sin"^(-1)((1)/(sqrt(2)))`

B

`"sin"^(-1)((1)/(4))`

C

`"sin"^(-1)((3)/(4))`

D

`"sin"^(-1)((sqrt(3))/(2))`

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the angle for the first secondary maximum in a Fraunhofer diffraction pattern at a single slit, we will follow these steps: ### Step 1: Understand the given information We are given: - Wavelength of light, \( \lambda = 5500 \, \text{Å} = 5500 \times 10^{-10} \, \text{m} \) - Angle for the first minimum, \( \theta_1 = 30^\circ \) ### Step 2: Use the formula for the first minimum In a single slit diffraction pattern, the position of the first minimum is given by the formula: \[ \sin \theta_1 = \frac{\lambda}{d} \] Where \( d \) is the width of the slit. ### Step 3: Calculate the slit width \( d \) Substituting the known values into the formula: \[ \sin(30^\circ) = \frac{1}{2} \] Thus, \[ \frac{1}{2} = \frac{5500 \times 10^{-10}}{d} \] Rearranging to find \( d \): \[ d = \frac{5500 \times 10^{-10}}{\frac{1}{2}} = 11000 \times 10^{-10} \, \text{m} = 1.1 \times 10^{-6} \, \text{m} \] ### Step 4: Use the formula for the first secondary maximum The position of the first secondary maximum occurs at: \[ \sin \theta = \frac{3}{2} \cdot \frac{\lambda}{d} \] ### Step 5: Substitute the values to find \( \theta \) Substituting the values of \( \lambda \) and \( d \): \[ \sin \theta = \frac{3}{2} \cdot \frac{5500 \times 10^{-10}}{1.1 \times 10^{-6}} \] Calculating the right-hand side: \[ \sin \theta = \frac{3}{2} \cdot \frac{5500 \times 10^{-10}}{1.1 \times 10^{-6}} = \frac{3 \cdot 5500}{2 \cdot 11000} = \frac{16500}{22000} = \frac{3}{4} \] ### Step 6: Find the angle \( \theta \) Now, we can find \( \theta \): \[ \theta = \sin^{-1} \left( \frac{3}{4} \right) \] ### Final Answer Thus, the angle for the first secondary maximum is: \[ \theta = \sin^{-1} \left( \frac{3}{4} \right) \]

To solve the problem of finding the angle for the first secondary maximum in a Fraunhofer diffraction pattern at a single slit, we will follow these steps: ### Step 1: Understand the given information We are given: - Wavelength of light, \( \lambda = 5500 \, \text{Å} = 5500 \times 10^{-10} \, \text{m} \) - Angle for the first minimum, \( \theta_1 = 30^\circ \) ### Step 2: Use the formula for the first minimum ...
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