Home
Class 12
PHYSICS
An optically active compound...

An optically active compound

A

rotates the plane of polarised light

B

changes the direction of polarised light

C

does not allow plane polarised light to pass through

D

none of these.

Text Solution

AI Generated Solution

The correct Answer is:
To determine the characteristics of an optically active compound, we can analyze the options provided in the question step by step. ### Step-by-Step Solution: 1. **Understanding Optically Active Compounds**: - An optically active compound is one that can rotate the plane of polarized light. This property is due to the presence of chiral centers in the molecule. 2. **Evaluating the Options**: - **Option 1: Rotates the plane of polarized light**: - This statement is true. Optically active compounds can indeed rotate the plane of polarized light, which is a defining characteristic. - **Option 2: Changes the direction of polarized light**: - This statement is false. While optically active compounds can rotate the plane of polarized light, they do not change its direction in the sense of altering the path of the light. - **Option 3: Does not allow plane polarized light to pass through**: - This statement is also false. Optically active compounds allow plane polarized light to pass through; they only affect its polarization state. - **Option 4: None of these**: - Since we have already established that the first option is correct, this option is also false. 3. **Conclusion**: - The only correct statement regarding optically active compounds is that they rotate the plane of polarized light. ### Final Answer: The correct option is: **Rotates the plane of polarized light**. ---
To determine the characteristics of an optically active compound, we can analyze the options provided in the question step by step. ### Step-by-Step Solution: 1. **Understanding Optically Active Compounds**: - An optically active compound is one that can rotate the plane of polarized light. This property is due to the presence of chiral centers in the molecule. 2. **Evaluating the Options**: ...
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    NCERT FINGERTIPS ENGLISH|Exercise HIGHER ORDER THINKING SKILLS|8 Videos

  • WAVE OPTICS

    NCERT FINGERTIPS ENGLISH|Exercise NCERT EXEMPLAR PROBLEMS|5 Videos

  • SEMICONDUCTOR ELECTRONICS : MATERIALS , DEVICES AND SIMPLE CIRCUITS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Write the name and structrue of the following optically active compounds with lowest moleuclar weight. i. alkane ii. Alkene iii. Alkyne iv. unsaturated hydrocabon v. alkyl halide vi. Alcohol vii. Acid viii. Amine.

An optically activ compound (A) has the molecular formula C_(6)H_(10) . The compound gives a ppt. When treated with Ag(NH_(3))_(2)OH . On catalytic hydrogenation, A yields B(C_(6)H_(14)) which is only optically inactive identify the total number of alphaH in product formed by treatment of A with O_(3)//H_(2)O_(2) then LAH and then H^(o+)//Delta

Identify the optically active compounds from the following

Number of optically active compounds out of following that can give Haloform reactions.

The number of optically active compounds in the isomers of C_(4)H_(9)Br is

Enantiomers may possess different rates of reactions with other optically active compounds.

Which optically active compound on reduction with LiAlH_(4) will give optically inactive compound?

The stereochemical formula of diastereomer 'Y' of optically active compound 'X' is, ( If X=2,3- Dihydroxybutanedioic acid. ).

Carbene intermediates are produced by the photolysis of diazomethane (CH_2N_2) or kenene (CH_2 = C = O) . They are also produced by the reaction of CHX_3 with base or by Simmons-Smith reaction. There are two types of carbenes, singlet and triplet. They are so called due to their spin state. An optically active alkene (I) with lowest molecular mass on hydrogenation gives optically inactive alkene, but on insertion of methylene carbene ( : CH_2) in (I) , it gives optically active compound (II) . The compounds (I) and (II) are : .