In a Young's double slit experiment, the source is white light. One of the holes is covered by a red filter and another by a blue filter. In this case

Options

A. there shall be alternate interference patterns of red and blue
B. there shall be an interference pattern for red distinct from that for blue
C. there shall be no interference fringes
D. there shall be an interference pattern for red mixing with one for blue.

Explanation

To solve the problem regarding the Young's double slit experiment with a red filter and a blue filter, we can follow these steps:

### Step 1: Understand the Setup
In a Young's double slit experiment, light passes through two slits, creating an interference pattern on a screen. The light source in this case is white light, which contains multiple wavelengths (colors).

**Hint:** Remember that white light is a combination of all visible colors.

### Step 2: Identify the Filters
One slit is covered with a red filter, and the other slit is covered with a blue filter. This means that the light passing through each slit will be of different colors: red light (longer wavelength) and blue light (shorter wavelength).

**Hint:** Consider how filters affect the wavelengths of light passing through them.

### Step 3: Analyze the Wavelengths
The red filter allows only red light to pass through, while the blue filter allows only blue light to pass through. Since red and blue light have different wavelengths, they will not have the same frequency.

**Hint:** Recall that interference patterns require coherent light sources, which means they must have the same wavelength and frequency.

### Step 4: Determine the Interference Condition
For an interference pattern to form, the light waves from both slits must be coherent. Since the red and blue light have different wavelengths and frequencies, they cannot create a stable interference pattern together.

**Hint:** Think about what coherence means in terms of wave properties.

### Step 5: Conclusion
Since the light from the two slits is not coherent due to the different wavelengths, there will be no interference fringes observed on the screen.

**Final Answer:** There shall be no interference fringes.