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A microwave telephone link operating at ...

A microwave telephone link operating at the central frequency of 10GHz has been established if 2% of this is available for microwave communication channel. Then how many telephone channels can be simultaneously granted if each telephone is allotted a bandwidth of 8 KHz?

A

`1.5xx10^(3)`

B

`3.5xx10^(2)`

C

`2.5xx10^(4)`

D

`4.5xx10^(6)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how many telephone channels can be simultaneously granted given the available bandwidth for communication. Here’s a step-by-step solution: ### Step 1: Determine the central frequency The central frequency of the microwave telephone link is given as: \[ \nu = 10 \text{ GHz} \] Converting this to Hertz: \[ \nu = 10 \times 10^9 \text{ Hz} = 10^{10} \text{ Hz} \] **Hint:** Remember that 1 GHz = \(10^9\) Hz. ### Step 2: Calculate the available bandwidth We know that only 2% of this frequency is available for the microwave communication channel. Therefore, we calculate 2% of \(10^{10}\) Hz: \[ \text{Available Bandwidth} = \frac{2}{100} \times 10^{10} \text{ Hz} \] \[ = 0.02 \times 10^{10} \text{ Hz} = 2 \times 10^8 \text{ Hz} \] **Hint:** To find a percentage, multiply the total by the percentage in decimal form. ### Step 3: Determine the bandwidth allotted per channel Each telephone channel is allotted a bandwidth of: \[ \text{Bandwidth per channel} = 8 \text{ kHz} \] Converting this to Hertz: \[ \text{Bandwidth per channel} = 8 \times 10^3 \text{ Hz} \] **Hint:** Remember that 1 kHz = \(10^3\) Hz. ### Step 4: Calculate the number of channels Now, we can find the number of telephone channels \(n\) that can be simultaneously granted using the formula: \[ n = \frac{\text{Total Bandwidth}}{\text{Bandwidth per channel}} \] Substituting the values we calculated: \[ n = \frac{2 \times 10^8 \text{ Hz}}{8 \times 10^3 \text{ Hz}} \] ### Step 5: Simplify the calculation Now, we simplify the expression: \[ n = \frac{2 \times 10^8}{8 \times 10^3} = \frac{2}{8} \times \frac{10^8}{10^3} = \frac{1}{4} \times 10^{5} = 0.25 \times 10^{5} = 2.5 \times 10^{4} \] **Hint:** When dividing powers of ten, subtract the exponents. ### Step 6: Convert to a more understandable number Finally, we can express \(2.5 \times 10^{4}\) in standard form: \[ n = 25000 \] Thus, the number of telephone channels that can be simultaneously granted is **25000**. **Final Answer:** 25000 telephone channels. ---

To solve the problem, we need to determine how many telephone channels can be simultaneously granted given the available bandwidth for communication. Here’s a step-by-step solution: ### Step 1: Determine the central frequency The central frequency of the microwave telephone link is given as: \[ \nu = 10 \text{ GHz} \] Converting this to Hertz: \[ \nu = 10 \times 10^9 \text{ Hz} = 10^{10} \text{ Hz} \] ...
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