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A TV transmission tower antenna is at a height of 20m. The percentage increase in area covered in case if the receiving antenna is at ground level to that at a height of 25 m is (Radius of earth `=6.4xx10^(6)m`)

A

2.48

B

`348.9%`

C

`150%`

D

`360.2%`

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The correct Answer is:
To solve the problem of finding the percentage increase in area covered by a TV transmission tower when the receiving antenna is at ground level compared to when it is at a height of 25 m, we can follow these steps: ### Step 1: Calculate the distance covered by the transmission tower antenna (Dt) The formula to calculate the distance (Dt) covered by the transmission tower is given by: \[ D_t = \sqrt{2 h_t R_e} \] where: - \( h_t = 20 \, \text{m} \) (height of the transmission tower) - \( R_e = 6.4 \times 10^6 \, \text{m} \) (radius of the Earth) Substituting the values: \[ D_t = \sqrt{2 \times 20 \times 6.4 \times 10^6} \] Calculating this gives: \[ D_t = \sqrt{2560000} \approx 1600 \, \text{m} = 16 \, \text{km} \] ### Step 2: Calculate the area covered by the transmission tower antenna (At) The area covered by the transmission tower can be calculated using the formula for the area of a circle: \[ A_t = \pi D_t^2 \] Substituting the value of \( D_t \): \[ A_t = \pi (16 \times 10^3)^2 \] Calculating this gives: \[ A_t \approx 3.14 \times 256 \times 10^6 \approx 803.84 \, \text{km}^2 \] ### Step 3: Calculate the maximum distance covered by the receiving tower antenna (Dm) The formula for the maximum distance (Dm) when the receiving antenna is at a height \( h_r \) is: \[ D_m = \sqrt{2 h_t R_e} + \sqrt{2 h_r R_e} \] where \( h_r = 25 \, \text{m} \). Substituting the values: \[ D_m = \sqrt{2 \times 20 \times 6.4 \times 10^6} + \sqrt{2 \times 25 \times 6.4 \times 10^6} \] Calculating each term: - First term: \( D_t \approx 16 \, \text{km} \) - Second term: \[ \sqrt{2 \times 25 \times 6.4 \times 10^6} = \sqrt{3200000} \approx 1788.85 \, \text{m} \approx 1.79 \, \text{km} \] Thus: \[ D_m \approx 16 + 1.79 \approx 33.79 \, \text{km} \] ### Step 4: Calculate the area covered by the receiving tower antenna (Ar) Using the area formula: \[ A_r = \pi D_m^2 \] Substituting the value of \( D_m \): \[ A_r = \pi (33.79 \times 10^3)^2 \] Calculating this gives: \[ A_r \approx 3.14 \times 1145.84 \times 10^6 \approx 3608.52 \, \text{km}^2 \] ### Step 5: Calculate the percentage increase in area The percentage increase in area is given by: \[ \text{Percentage Increase} = \frac{A_r - A_t}{A_t} \times 100 \] Substituting the areas: \[ \text{Percentage Increase} = \frac{3608.52 - 803.84}{803.84} \times 100 \] Calculating this gives: \[ \text{Percentage Increase} \approx \frac{2804.68}{803.84} \times 100 \approx 348.9\% \] ### Final Answer: The percentage increase in area covered when the receiving antenna is at ground level compared to when it is at a height of 25 m is approximately **348.9%**.

To solve the problem of finding the percentage increase in area covered by a TV transmission tower when the receiving antenna is at ground level compared to when it is at a height of 25 m, we can follow these steps: ### Step 1: Calculate the distance covered by the transmission tower antenna (Dt) The formula to calculate the distance (Dt) covered by the transmission tower is given by: \[ D_t = \sqrt{2 h_t R_e} \] where: ...
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