A fax message is to be sent from Delhi to washington via a geostationary satellite. Calculate the minimum time delay between
the dispatch and its getting received. Take
height of the geostationary satellite = 36000
km.

Options

A. `72xx10^(3)km`
B. `12xx10^(3)km`
C. `27xx10^(3)km`
D. `18xx10^(3)km`

Explanation

To calculate the minimum time delay for a fax message sent from Delhi to Washington via a geostationary satellite, we can follow these steps:

### Step 1: Understand the Distance
The height of the geostationary satellite is given as 36,000 km. Since the signal has to travel to the satellite and then back to Earth, we need to calculate the total distance.

**Total Distance (s)** = Distance to Satellite + Distance back to Earth
**Total Distance (s)** = 36,000 km + 36,000 km = 72,000 km

### Step 2: Convert Distance to Meters
Since the speed of light is typically expressed in meters per second, we need to convert the distance from kilometers to meters.

**Total Distance in meters** = 72,000 km × 1,000 m/km = 72,000,000 m

### Step 3: Use the Speed of Light
The speed of light (c) is approximately \(3 \times 10^8\) m/s.

### Step 4: Calculate Time Delay
We can calculate the time delay using the formula:

\[ \text{Time Delay (t)} = \frac{\text{Distance (s)}}{\text{Speed of Light (c)}} \]

Substituting the values we have:

\[ t = \frac{72,000,000 \text{ m}}{3 \times 10^8 \text{ m/s}} \]

### Step 5: Simplify the Calculation
Now, we can simplify the calculation:

\[ t = \frac{72,000,000}{300,000,000} = 0.24 \text{ seconds} \]

### Conclusion
The minimum time delay between the dispatch and receiving of the fax message is approximately **0.24 seconds**.

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