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A multimode graded index fibre exhibits ...

A multimode graded index fibre exhibits total pulse broadening of 0.1 us cover a distance of 1.5km. What is the maximum possible band width on the link assuming no inter symbol interference?

A

10MHz

B

7.5M Hz

C

5MHz

D

2.5MHz

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The correct Answer is:
To solve the problem of finding the maximum possible bandwidth on a multimode graded index fiber given the total pulse broadening, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Total pulse broadening (Δt) = 0.1 µs = 0.1 × 10^(-6) s - Distance covered = 1.5 km (not directly needed for this calculation) 2. **Understand the Relationship Between Bandwidth and Pulse Broadening:** - The maximum possible bandwidth (B) can be calculated using the formula: \[ B = \frac{1}{2 \Delta t} \] - Here, Δt is the pulse broadening time. 3. **Substitute the Values into the Formula:** - Substitute Δt = 0.1 × 10^(-6) s into the formula: \[ B = \frac{1}{2 \times (0.1 \times 10^{-6})} \] 4. **Calculate the Bandwidth:** - First, calculate the denominator: \[ 2 \times (0.1 \times 10^{-6}) = 0.2 \times 10^{-6} = 2 \times 10^{-7} \text{ seconds} \] - Now, calculate the bandwidth: \[ B = \frac{1}{2 \times 10^{-7}} = 5 \times 10^{6} \text{ Hz} = 5 \text{ MHz} \] 5. **Conclusion:** - The maximum possible bandwidth on the link is **5 MHz**. ### Final Answer: The maximum possible bandwidth on the link is **5 MHz**. ---

To solve the problem of finding the maximum possible bandwidth on a multimode graded index fiber given the total pulse broadening, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Total pulse broadening (Δt) = 0.1 µs = 0.1 × 10^(-6) s - Distance covered = 1.5 km (not directly needed for this calculation) ...
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