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Two identical capacitors 1 and 2 are con...

Two identical capacitors `1` and `2` are connected in series to a batery as shown in figure. Capacitor `2` contains a dielectric slab of dieletric constant `k` as shown. `Q_(1)` and `Q_(2)` are the charges stored in the capacitors. Now the dielectirc slab us removed and the corresponding charges are `Q'_(1)` and `Q'_(2)`. Then

A

`(Q'_(1))/(Q_(1)) = (K+1)/(K)`

B

`(Q'_(2))/(Q_(2)) = (K+1)/(2)`

C

`(Q'_(2))/(Q_(2)) = (K+1)/(2K)`

D

`(Q'_(1))/(Q_(1)) = (K)/(2)`

Text Solution

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The correct Answer is:
C
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