Refraction of light from air to glas and from air to water are shown in figure (i) and figure (ii) below. The value of the angle `theta` in the case of refraction as shown in figure (iii) will be

Options

A. `30^(@)`
B. `35^(@)`
C. `60^(@)`
D. `41^(@)`

Answer

B

Explanation

Using Snell's law, `.^(a)mu_(g) = (sin60^(@))/(sin35^(@)), .^(@)mu_(w) = (sin60^(@))/(sin 41^(@))`
and `.^(w)mu_(g) = (sin 41^(@))/(sin theta)`
`.^(@)mu_(w) xx .^(w)mu_(g)`
`rArr (sin 60^(@))/(sin 41^(@)) xx (sin 41^(@))/(sin theta) = (sin60^(@))/(sin35^(@)) rArr sin theta = sin 35^(@)` or `theta = 35^(@)`