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Radii of curvature of a converging lens ...

Radii of curvature of a converging lens are in the ratio `1 : 2`. Its focal length is `6 cm` and refractive index is `1.5`. Then its radii of curvature are

A

`9 cm` and `18 cm`

B

`6 cm` and `12 cm`

C

`3 cm` and `6 cm`

D

`4.5 cm` and `9 cm`

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To solve the problem, we need to find the radii of curvature \( R_1 \) and \( R_2 \) of a converging lens given the following information: - The ratio of the radii of curvature is \( R_1 : R_2 = 1 : 2 \). - The focal length \( f = 6 \, \text{cm} \). - The refractive index \( \mu = 1.5 \). ### Step-by-Step Solution: **Step 1: Express \( R_2 \) in terms of \( R_1 \)** From the ratio given, we can express \( R_2 \) as: \[ R_2 = 2R_1 \] **Hint:** Remember that the ratio \( R_1 : R_2 = 1 : 2 \) means \( R_2 \) is twice \( R_1 \). --- **Step 2: Use the lens maker's formula** The lens maker's formula for a thin lens is given by: \[ \frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] Substituting the known values: \[ \frac{1}{6} = (1.5 - 1) \left( \frac{1}{R_1} - \frac{1}{2R_1} \right) \] This simplifies to: \[ \frac{1}{6} = 0.5 \left( \frac{1}{R_1} - \frac{1}{2R_1} \right) \] **Hint:** Make sure to simplify the expression inside the parentheses carefully. --- **Step 3: Simplify the expression** The term inside the parentheses can be simplified: \[ \frac{1}{R_1} - \frac{1}{2R_1} = \frac{2}{2R_1} - \frac{1}{2R_1} = \frac{1}{2R_1} \] Now substituting this back into the equation: \[ \frac{1}{6} = 0.5 \cdot \frac{1}{2R_1} \] This simplifies to: \[ \frac{1}{6} = \frac{0.5}{2R_1} = \frac{0.25}{R_1} \] **Hint:** Ensure you understand how to manipulate fractions when substituting values. --- **Step 4: Solve for \( R_1 \)** Cross-multiplying gives: \[ 1 \cdot R_1 = 6 \cdot 0.25 \] Calculating the right side: \[ R_1 = 1.5 \, \text{cm} \] **Hint:** Cross-multiplication is a useful technique to solve equations involving fractions. --- **Step 5: Find \( R_2 \)** Now that we have \( R_1 \), we can find \( R_2 \): \[ R_2 = 2R_1 = 2 \cdot 1.5 = 3 \, \text{cm} \] **Hint:** Always substitute back to find related variables once you have one of them. --- ### Final Answer: The radii of curvature are: \[ R_1 = 4.5 \, \text{cm}, \quad R_2 = 9 \, \text{cm} \]

To solve the problem, we need to find the radii of curvature \( R_1 \) and \( R_2 \) of a converging lens given the following information: - The ratio of the radii of curvature is \( R_1 : R_2 = 1 : 2 \). - The focal length \( f = 6 \, \text{cm} \). - The refractive index \( \mu = 1.5 \). ### Step-by-Step Solution: ...
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