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A ray of light passes through an equilat...

A ray of light passes through an equilateral prism (refractive index `1.5`) such that angle of incidence is equal to angle of emergence and the latter is equal to `3//4 th` of the angle of prism. Calculate the angle of deviation.

A

`60^(@)`

B

`30^(@)`

C

`45^(@)`

D

`120^(@)`

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The correct Answer is:
To solve the problem step by step, we will follow the information provided in the question and the video transcript. ### Step 1: Understand the Given Information - We have an equilateral prism, which means the angle of the prism \( A = 60^\circ \). - The refractive index \( n = 1.5 \). - The angle of incidence \( i \) is equal to the angle of emergence \( e \). - The angle of emergence \( e \) is given as \( \frac{3}{4} \) of the angle of the prism \( A \). ### Step 2: Express the Angles From the information provided: - Since the angle of emergence \( e = \frac{3}{4} A \), we can calculate \( e \): \[ e = \frac{3}{4} \times 60^\circ = 45^\circ \] - Since \( i = e \), we also have: \[ i = 45^\circ \] ### Step 3: Use the Formula for Angle of Deviation The formula for the angle of deviation \( \delta \) is given by: \[ \delta = i + e - A \] Substituting the values we have: \[ \delta = 45^\circ + 45^\circ - 60^\circ \] ### Step 4: Calculate the Angle of Deviation Now, we can perform the calculation: \[ \delta = 90^\circ - 60^\circ = 30^\circ \] ### Step 5: Conclusion Thus, the angle of deviation \( \delta \) is: \[ \delta = 30^\circ \] ### Final Answer The angle of deviation is \( 30^\circ \). ---

To solve the problem step by step, we will follow the information provided in the question and the video transcript. ### Step 1: Understand the Given Information - We have an equilateral prism, which means the angle of the prism \( A = 60^\circ \). - The refractive index \( n = 1.5 \). - The angle of incidence \( i \) is equal to the angle of emergence \( e \). - The angle of emergence \( e \) is given as \( \frac{3}{4} \) of the angle of the prism \( A \). ...
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