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Heat is supplied to a diatomic gas at co...

Heat is supplied to a diatomic gas at constant pressure.
The ratio of `DeltaQ : DeltaU : DeltaW` is a) 5: 3: 2 b) 7: 5: 2 c) 2: 3: 5 d) 2: 5: 7

A

`5:3:2`

B

`7:5:2`

C

`2:3:5`

D

`2:5:7`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of \(\Delta Q\), \(\Delta U\), and \(\Delta W\) for a diatomic gas at constant pressure, we can follow these steps: ### Step 1: Identify the specific heats For a diatomic gas, the specific heat at constant volume (\(C_V\)) and constant pressure (\(C_P\)) are given as: - \(C_V = \frac{5}{2} R\) - \(C_P = \frac{7}{2} R\) ### Step 2: Write the expressions for \(\Delta Q\), \(\Delta U\), and \(\Delta W\) Using the definitions: - The heat supplied to the gas at constant pressure is given by: \[ \Delta Q = n C_P \Delta T \] - The change in internal energy is given by: \[ \Delta U = n C_V \Delta T \] - The work done by the gas at constant pressure can be expressed as: \[ \Delta W = \Delta Q - \Delta U \] ### Step 3: Substitute the expressions for \(\Delta Q\) and \(\Delta U\) Substituting the values of \(C_P\) and \(C_V\) into the equations: - \(\Delta Q = n \left(\frac{7}{2} R\right) \Delta T\) - \(\Delta U = n \left(\frac{5}{2} R\right) \Delta T\) ### Step 4: Calculate \(\Delta W\) Now, substituting \(\Delta Q\) and \(\Delta U\) into the equation for \(\Delta W\): \[ \Delta W = \Delta Q - \Delta U = n \left(\frac{7}{2} R\right) \Delta T - n \left(\frac{5}{2} R\right) \Delta T \] \[ \Delta W = n \left(\left(\frac{7}{2} R - \frac{5}{2} R\right) \Delta T\right) = n \left(\frac{2}{2} R\right) \Delta T = n R \Delta T \] ### Step 5: Form the ratio \(\Delta Q : \Delta U : \Delta W\) Now we can express the ratio: \[ \Delta Q : \Delta U : \Delta W = n \left(\frac{7}{2} R \Delta T\right) : n \left(\frac{5}{2} R \Delta T\right) : n \left(R \Delta T\right) \] Cancelling \(n\) and \(\Delta T\) from all terms, we have: \[ \Delta Q : \Delta U : \Delta W = \frac{7}{2} R : \frac{5}{2} R : R \] This simplifies to: \[ \Delta Q : \Delta U : \Delta W = 7 : 5 : 2 \] ### Final Answer Thus, the ratio of \(\Delta Q : \Delta U : \Delta W\) is: \[ \text{Option (b) } 7 : 5 : 2 \] ---

To solve the problem of finding the ratio of \(\Delta Q\), \(\Delta U\), and \(\Delta W\) for a diatomic gas at constant pressure, we can follow these steps: ### Step 1: Identify the specific heats For a diatomic gas, the specific heat at constant volume (\(C_V\)) and constant pressure (\(C_P\)) are given as: - \(C_V = \frac{5}{2} R\) - \(C_P = \frac{7}{2} R\) ### Step 2: Write the expressions for \(\Delta Q\), \(\Delta U\), and \(\Delta W\) ...
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