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An ideal gs at pressure P is adiabatical...

An ideal gs at pressure P is adiabatically compressed so that its density becomes n times the initial vlaue The final pressure of the gas will be `(gamma=(C_(P))/(C_(V)))`

A

`ngammaP`

B

`(n-gamma)P`

C

`n(gamma-1)P`

D

`n(1-gamma)P`

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The correct Answer is:
To solve the problem of finding the final pressure of an ideal gas that is adiabatically compressed such that its density becomes n times the initial value, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Adiabatic Process**: For an adiabatic process involving an ideal gas, the relationship between pressure (P) and volume (V) is given by the equation: \[ PV^\gamma = \text{constant} \] where \(\gamma = \frac{C_P}{C_V}\) is the specific heat ratio. 2. **Define Initial Conditions**: Let \(P_1\) be the initial pressure and \(V_1\) be the initial volume of the gas. Therefore, we can write: \[ P_1 V_1^\gamma = \text{constant} \] 3. **Express Density**: The density of a gas is defined as: \[ \rho = \frac{m}{V} \] where \(m\) is the mass of the gas. If we denote the initial density as \(\rho_1\), then the initial volume can be expressed as: \[ V_1 = \frac{m}{\rho_1} \] 4. **Final Density**: According to the problem, the final density \(\rho_2\) becomes \(n\) times the initial density: \[ \rho_2 = n \rho_1 \] The final volume \(V_2\) can then be expressed as: \[ V_2 = \frac{m}{\rho_2} = \frac{m}{n \rho_1} = \frac{V_1}{n} \] 5. **Apply the Adiabatic Condition**: Now, we can apply the adiabatic condition to the final state: \[ P_2 V_2^\gamma = P_1 V_1^\gamma \] Substituting \(V_2 = \frac{V_1}{n}\) into the equation gives: \[ P_2 \left(\frac{V_1}{n}\right)^\gamma = P_1 V_1^\gamma \] 6. **Rearranging the Equation**: This can be rearranged to find \(P_2\): \[ P_2 = P_1 \left(n^{-\gamma}\right) V_1^{\gamma} \cdot V_1^{\gamma} \] Simplifying this gives: \[ P_2 = P_1 n^{\gamma} \] 7. **Final Expression**: Therefore, the final pressure of the gas after adiabatic compression is: \[ P_2 = n^{\gamma} P_1 \] ### Final Answer: The final pressure of the gas after adiabatic compression is: \[ P_2 = n^{\gamma} P \] where \(P\) is the initial pressure of the gas.

To solve the problem of finding the final pressure of an ideal gas that is adiabatically compressed such that its density becomes n times the initial value, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Adiabatic Process**: For an adiabatic process involving an ideal gas, the relationship between pressure (P) and volume (V) is given by the equation: \[ PV^\gamma = \text{constant} \] ...
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