Consider a heat engine as shown in (figure). `Q_(1) and Q_(2)` are heat added to heat bath `T_(1)` and heat taken from `T_(2)` one cycle of engine. `W` is the mechanical work done on the engine.

If `Wgt0`, then possibillities are:

Options

A. `Q_1>Q_2>0`
B. `Q_2>Q_1>0`
C. `Q_2` `<` `Q_1` `<` `0`
D. `Q1<0,Q2>0`

Answer

B

Explanation

Here the given figure reprsents the working of a refrigeratiro
`Q_(1)=Q_(2)+W`
If ,`Wgt 0`, then `Q_(1)gtQ_(2)gt0`
If `Q_(2)` is negative `Q_(1)` is also negative
`therefore Q_(2)ltQ_(1)lt0`
Hence (iii) is also correct.