A refrigerator is to maintain eatables kept inside at `7^(@)C`. The coefficient opf performance of refrigerator if room temperature is `38^(@)C` is

Options

A. a. 15.5
B. b. 16.3
C. c. 20.1
D. d. 9.03

Explanation

To find the coefficient of performance (COP) of the refrigerator, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Temperatures**:
- The temperature inside the refrigerator (T1) is given as \(7^\circ C\).
- The room temperature (T2) is given as \(38^\circ C\).

2. **Convert Celsius to Kelvin**:
- To convert Celsius to Kelvin, we use the formula:
\[ T(K) = T(°C) + 273 \]
- For T1:
\[ T1 = 7 + 273 = 280 \, K \]
- For T2:
\[ T2 = 38 + 273 = 311 \, K \]

3. **Use the Coefficient of Performance Formula**:
- The formula for the coefficient of performance (COP) for a refrigerator is:
\[ COP = \frac{T1}{T2 - T1} \]

4. **Calculate the Difference in Temperature**:
- Calculate \(T2 - T1\):
\[ T2 - T1 = 311 \, K - 280 \, K = 31 \, K \]

5. **Substitute Values into the COP Formula**:
- Now substitute T1 and \(T2 - T1\) into the COP formula:
\[ COP = \frac{280}{31} \]

6. **Calculate COP**:
- Now perform the division:
\[ COP \approx 9.03 \]

### Final Answer:
The coefficient of performance (COP) of the refrigerator is approximately **9.03**.