The coefficient of performance of refrigerator, whose efficiencty is 25% is

Options

A. 1
B. 3
C. 5
D. 7

Explanation

To find the coefficient of performance (COP) of a refrigerator given its efficiency, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Given Information**:
- The efficiency (η) of the refrigerator is given as 25%. This can be expressed in decimal form as:
\[ \eta = \frac{25}{100} = 0.25 \]

2. **Use the Formula for Coefficient of Performance**:
- The coefficient of performance (β) for a refrigerator can be calculated using the formula:
\[ \beta = \frac{1 - \eta}{\eta} \]

3. **Substitute the Efficiency Value into the Formula**:
- Plugging in the value of η into the formula:
\[ \beta = \frac{1 - 0.25}{0.25} \]

4. **Calculate the Numerator**:
- Calculate \(1 - 0.25\):
\[ 1 - 0.25 = 0.75 \]

5. **Calculate the Coefficient of Performance**:
- Now substitute the value back into the equation:
\[ \beta = \frac{0.75}{0.25} \]

6. **Perform the Division**:
- Calculate \(0.75 \div 0.25\):
\[ \beta = 3 \]

7. **Conclusion**:
- Therefore, the coefficient of performance of the refrigerator is:
\[ \beta = 3 \]

### Final Answer:
The coefficient of performance of the refrigerator is **3**.

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