The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacumm is equal to

Options

A. the speed of light in vacuum
B. reciprocal of speed of light in vacuum
C. the ratio of magnetic permeability to the electric susceptibility of vacuum
D. unity

Explanation

To find the ratio of the amplitude of the magnetic field (B₀) to the amplitude of the electric field (E₀) for an electromagnetic wave propagating in vacuum, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship Between Electric and Magnetic Fields**:
In an electromagnetic wave, the electric field (E) and magnetic field (B) are related to the speed of light (c) in vacuum. This relationship is given by the equation:
\[ c = \frac{E_0}{B_0} \]
where \(E_0\) is the amplitude of the electric field and \(B_0\) is the amplitude of the magnetic field.

2. **Rearranging the Equation**:
From the equation \(c = \frac{E_0}{B_0}\), we can rearrange it to find the ratio of the magnetic field to the electric field:
\[ \frac{B_0}{E_0} = \frac{1}{c} \]

3. **Conclusion**:
The ratio of the amplitude of the magnetic field to the amplitude of the electric field for an electromagnetic wave propagating in vacuum is equal to the reciprocal of the speed of light in vacuum:
\[ \frac{B_0}{E_0} = \frac{1}{c} \]

4. **Final Answer**:
Therefore, the correct answer is that the ratio of the amplitude of the magnetic field to the amplitude of the electric field is equal to the reciprocal of the speed of light in vacuum.