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An electromagnetic wave of intensity I f...

An electromagnetic wave of intensity I falls on a surface kept in vacuum and exerts radiation pressure `p` on it.Which of the following are true ?

A

Radiation pressure is `I//c` if the wave is totally absorbed.

B

Radiation pressure is `I//c` if the wave is totally reflected.

C

Radiation pressure is 2 `I//c` if the wave is totally reflected.

D

Radiation pressure is in the range `I//cltplt2I//c` for real surfaces.

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To solve the problem regarding the radiation pressure exerted by an electromagnetic wave of intensity \( I \) on a surface in vacuum, we can analyze the situation based on the principles of momentum transfer and the behavior of electromagnetic waves upon absorption and reflection. ### Step-by-Step Solution: 1. **Understanding Radiation Pressure**: - Radiation pressure \( P \) is defined as the force per unit area exerted by electromagnetic waves on a surface. It can be derived from the change in momentum of the wave when it interacts with the surface. 2. **Case 1: Total Absorption**: - When the electromagnetic wave is totally absorbed by the surface, the momentum change per unit area per unit time is given by: \[ P = \frac{I}{c} \] - Here, \( I \) is the intensity of the wave and \( c \) is the speed of light. The momentum of the absorbed wave contributes to the radiation pressure. 3. **Case 2: Total Reflection**: - When the wave is totally reflected, the momentum change is different. The momentum of the incoming wave is \( \frac{I}{c} \) and the momentum of the reflected wave is also \( \frac{I}{c} \) but in the opposite direction. - Therefore, the total change in momentum per unit area per unit time is: \[ P = \frac{I}{c} - (-\frac{I}{c}) = \frac{I}{c} + \frac{I}{c} = \frac{2I}{c} \] 4. **Case 3: Real Surfaces**: - For real surfaces that are neither perfect absorbers nor perfect reflectors, the radiation pressure will fall between the two extremes: \[ \frac{I}{c} < P < \frac{2I}{c} \] 5. **Conclusion**: - From the analysis, we can conclude the following: - Radiation pressure is \( \frac{I}{c} \) if the wave is totally absorbed. (True) - Radiation pressure is \( \frac{2I}{c} \) if the wave is totally reflected. (True) - Radiation pressure for real surfaces lies in the range \( \frac{I}{c} < P < \frac{2I}{c} \). (True) ### Final Statements: - The statements regarding radiation pressure are true: 1. Radiation pressure is \( \frac{I}{c} \) if the wave is totally absorbed. (True) 2. Radiation pressure is \( \frac{2I}{c} \) if the wave is totally reflected. (True) 3. Radiation pressure is in the range \( \frac{I}{c} < P < \frac{2I}{c} \) for real surfaces. (True)

To solve the problem regarding the radiation pressure exerted by an electromagnetic wave of intensity \( I \) on a surface in vacuum, we can analyze the situation based on the principles of momentum transfer and the behavior of electromagnetic waves upon absorption and reflection. ### Step-by-Step Solution: 1. **Understanding Radiation Pressure**: - Radiation pressure \( P \) is defined as the force per unit area exerted by electromagnetic waves on a surface. It can be derived from the change in momentum of the wave when it interacts with the surface. 2. **Case 1: Total Absorption**: ...
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