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The rms value of the electric field of t...

The rms value of the electric field of the light from the sun is `720 N//C` The total energy density of the electromagnetic wave is

A

`3.3xx10^(-3)"J m"^(-3)`

B

`4.58xx10^(-6)"J m"^(-3)`

C

`6.37xx10^(-9)"J m"^(-3)`

D

`81.35xx10^(-12)"J m"^(-3)`.

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The correct Answer is:
To find the total energy density of the electromagnetic wave given the RMS value of the electric field, we can follow these steps: ### Step 1: Understand the formula for energy density The total energy density \( U \) of an electromagnetic wave can be expressed as the sum of the energy density due to the electric field \( U_E \) and the energy density due to the magnetic field \( U_B \): \[ U = U_E + U_B \] ### Step 2: Write the formula for energy density due to the electric field The energy density due to the electric field is given by the formula: \[ U_E = \frac{1}{2} \epsilon_0 E^2 \] where: - \( \epsilon_0 \) is the permittivity of free space, approximately \( 8.85 \times 10^{-12} \, \text{F/m} \) - \( E \) is the RMS value of the electric field. ### Step 3: Write the formula for energy density due to the magnetic field The energy density due to the magnetic field is given by: \[ U_B = \frac{1}{2} \frac{B^2}{\mu_0} \] However, for electromagnetic waves, the energy densities due to the electric and magnetic fields are equal: \[ U_E = U_B \] Thus, we can express the total energy density as: \[ U = 2 U_E \] ### Step 4: Substitute the expression for \( U_E \) into the total energy density formula Substituting \( U_E \) into the total energy density formula gives: \[ U = 2 \left( \frac{1}{2} \epsilon_0 E^2 \right) = \epsilon_0 E^2 \] ### Step 5: Substitute the values Now, we can substitute the values into the equation. Given that \( E = 720 \, \text{N/C} \): \[ U = \epsilon_0 E^2 = (8.85 \times 10^{-12} \, \text{F/m}) \times (720 \, \text{N/C})^2 \] ### Step 6: Calculate the result Calculating the above expression: \[ U = 8.85 \times 10^{-12} \times 720^2 \] \[ = 8.85 \times 10^{-12} \times 518400 \] \[ \approx 4.587 \times 10^{-6} \, \text{J/m}^3 \] ### Final Answer The total energy density of the electromagnetic wave is approximately: \[ U \approx 4.587 \times 10^{-6} \, \text{J/m}^3 \]

To find the total energy density of the electromagnetic wave given the RMS value of the electric field, we can follow these steps: ### Step 1: Understand the formula for energy density The total energy density \( U \) of an electromagnetic wave can be expressed as the sum of the energy density due to the electric field \( U_E \) and the energy density due to the magnetic field \( U_B \): \[ U = U_E + U_B \] ...
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