According to bohr's theory, the wave number of last line of balmer series is `(R =1.1xx10^(7)m^(-1))`

Options

A. `5.5xx10^5m^(-1)`
B. `4.4xx10^7m^(-1)`
C. `2.75xx10^6m^(-1)`
D. `2.75xx10^8m^(-1)`

Answer

C

Explanation

For last line of lyman series `n_1=2` and `n_2=oo`
`(1)/(lambda)=R[(1)/(n_1^2)-(1)/(n_2^2)]=(1.1xx10^7)/(4)m^-1=2.75xx10^6m^-1`