According to second postulate of bohr model, the agnular momentum `(L_n)` of `n^(th)` possible orbit of hydrogen atom is given by

Options

A. `(h)/(2pin)`
B. `(nh)/(2pi)`
C. `(2pin)/(h)`
D. `(2pi)/(nh)`

Explanation

To find the angular momentum \( L_n \) of the \( n^{th} \) possible orbit of a hydrogen atom according to the second postulate of the Bohr model, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Bohr Model**: The Bohr model of the hydrogen atom states that electrons move in fixed orbits around the nucleus and that these orbits are quantized.

2. **Identify the Postulate**: According to the second postulate of the Bohr model, the angular momentum of an electron in a given orbit is quantized and is given by the formula:
\[ L_n = n \frac{h}{2\pi} \]
where:
- \( L_n \) is the angular momentum of the \( n^{th} \) orbit,
- \( n \) is the principal quantum number (an integer),
- \( h \) is Planck's constant.

3. **Write the Formula**: Based on the postulate, we can express the angular momentum as:
\[ L_n = n \frac{h}{2\pi} \]

4. **Conclusion**: Therefore, the angular momentum \( L_n \) of the \( n^{th} \) possible orbit of the hydrogen atom is given by the formula:
\[ L_n = n \frac{h}{2\pi} \]

### Final Answer:
The angular momentum \( L_n \) of the \( n^{th} \) orbit of a hydrogen atom is:
\[ L_n = n \frac{h}{2\pi} \]

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