In Bohr model of the hydrogen atom, the lowest orbit corresponds to

Options

A. infinite energy
B. maximum energy
C. minimum energy
D. zero energy

Explanation

To solve the question regarding the lowest orbit in the Bohr model of the hydrogen atom, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Bohr Model**: The Bohr model describes the hydrogen atom as having discrete energy levels (orbits) where electrons can exist without radiating energy.

2. **Energy of nth Orbit**: The energy of an electron in the nth orbit is given by the formula:
\[ E_n = -\frac{13.6 \, \text{eV} \cdot z^2}{n^2} \]
where \( z \) is the atomic number (for hydrogen, \( z = 1 \)) and \( n \) is the principal quantum number (orbit number).

3. **Calculate Energy for n=1**: For the lowest orbit (n=1):
\[ E_1 = -\frac{13.6 \, \text{eV} \cdot 1^2}{1^2} = -13.6 \, \text{eV} \]

4. **Compare with Higher Orbits**: For higher orbits, calculate the energy:
- For \( n=2 \):
\[ E_2 = -\frac{13.6 \, \text{eV} \cdot 1^2}{2^2} = -\frac{13.6}{4} = -3.4 \, \text{eV} \]
- For \( n=3 \):
\[ E_3 = -\frac{13.6 \, \text{eV} \cdot 1^2}{3^2} = -\frac{13.6}{9} \approx -1.51 \, \text{eV} \]

5. **Identify the Lowest Energy**: The energy values show that as \( n \) increases, the energy becomes less negative (increases). Therefore, the lowest orbit, which corresponds to the lowest energy, is when \( n=1 \).

6. **Conclusion**: The lowest orbit corresponds to \( n=1 \) with an energy of \( -13.6 \, \text{eV} \).

### Final Answer:
The lowest orbit in the Bohr model of the hydrogen atom corresponds to \( n=1 \) with an energy of \( -13.6 \, \text{eV} \).

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