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Mobilities of electorns and holes in a sample of intrinsic germanium at room temperature are `0.54m^(2)V^(-1)s^(-1)` and `0.18m^(2)V^(-1)s^(-1)` respectively.
If the electron and hole densities are equal to `3.6xx10^(19)m^(-3)` calculate the germanium conductivity.

A

`4.14 S m^(-1)`

B

`2.12 S m^(-1)`

C

`1.13 S m^(-1)`

D

`5.6 S m^(-1)`

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The correct Answer is:
To calculate the conductivity of intrinsic germanium, we can use the formula for conductivity (\( \sigma \)) in terms of the mobilities of electrons and holes and their respective densities: \[ \sigma = q (n \mu_n + p \mu_p) \] Where: - \( \sigma \) = conductivity - \( q \) = charge of an electron (approximately \( 1.6 \times 10^{-19} \, \text{C} \)) - \( n \) = density of electrons - \( p \) = density of holes - \( \mu_n \) = mobility of electrons - \( \mu_p \) = mobility of holes ### Step-by-Step Solution: 1. **Identify Given Values:** - Mobility of electrons, \( \mu_n = 0.54 \, \text{m}^2/\text{V}\cdot\text{s} \) - Mobility of holes, \( \mu_p = 0.18 \, \text{m}^2/\text{V}\cdot\text{s} \) - Density of electrons, \( n = 3.6 \times 10^{19} \, \text{m}^{-3} \) - Density of holes, \( p = 3.6 \times 10^{19} \, \text{m}^{-3} \) 2. **Substitute Values into the Conductivity Formula:** \[ \sigma = q (n \mu_n + p \mu_p) \] \[ \sigma = (1.6 \times 10^{-19}) \left( (3.6 \times 10^{19}) \times 0.54 + (3.6 \times 10^{19}) \times 0.18 \right) \] 3. **Factor Out Common Terms:** Since \( n = p \), we can factor out \( n \): \[ \sigma = q n (\mu_n + \mu_p) \] \[ \sigma = (1.6 \times 10^{-19}) (3.6 \times 10^{19}) \left( 0.54 + 0.18 \right) \] 4. **Calculate the Sum of Mobilities:** \[ \mu_n + \mu_p = 0.54 + 0.18 = 0.72 \, \text{m}^2/\text{V}\cdot\text{s} \] 5. **Substitute Back into the Formula:** \[ \sigma = (1.6 \times 10^{-19}) (3.6 \times 10^{19}) (0.72) \] 6. **Calculate the Product:** \[ \sigma = (1.6 \times 3.6 \times 0.72) \times 10^{-19 + 19} \] \[ \sigma = (3.6864) \, \text{S/m} \] 7. **Final Calculation:** \[ \sigma \approx 3.69 \, \text{S/m} \] ### Final Answer: The conductivity of intrinsic germanium at room temperature is approximately \( 3.69 \, \text{S/m} \).

To calculate the conductivity of intrinsic germanium, we can use the formula for conductivity (\( \sigma \)) in terms of the mobilities of electrons and holes and their respective densities: \[ \sigma = q (n \mu_n + p \mu_p) \] Where: - \( \sigma \) = conductivity ...
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NCERT FINGERTIPS ENGLISH-SEMICONDUCTOR ELECTRONICS : MATERIALS , DEVICES AND SIMPLE CIRCUITS -Assertion And Reason
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