A potential barrier of 0.3 V exists across a p-n junction. If the depletion region is 1 `mu`m wide, what is the intensity of electric field in this region?

Options

A. `2xx10^5 V m^(-1)`
B. `3xx10^5 V m^(-1)`
C. `4xx10^5 V m^(-1)`
D. `5xx10^5 V m^(-1)`

Explanation

To find the intensity of the electric field in the depletion region of a p-n junction, we can use the formula:

\[ E = \frac{V}{d} \]

where:
- \( E \) is the electric field intensity,
- \( V \) is the potential barrier (voltage) across the junction,
- \( d \) is the width of the depletion region.

### Step-by-Step Solution:

1. **Identify the given values:**
- Potential barrier \( V = 0.3 \, \text{V} \)
- Width of the depletion region \( d = 1 \, \mu m = 1 \times 10^{-6} \, \text{m} \)

2. **Convert the width into meters:**
- \( d = 1 \, \mu m = 1 \times 10^{-6} \, \text{m} \)

3. **Substitute the values into the formula:**
\[ E = \frac{0.3 \, \text{V}}{1 \times 10^{-6} \, \text{m}} \]

4. **Calculate the electric field:**
\[ E = 0.3 \times 10^{6} \, \text{V/m} \]
\[ E = 3 \times 10^{5} \, \text{V/m} \]

5. **Final Result:**
- The intensity of the electric field in the depletion region is \( E = 3 \times 10^{5} \, \text{V/m} \).